Question

我一直在谷歌搜索我的问题2天，使用nodeJs在socket.io上动态创建房间。当我为服务器创建一个房间时，我这样做：

socket.on('follow_me', function (user_id) { //I use the user_id of the user to create room

    socket.join(user_id);

    console.log(server.sockets.manager.rooms);
});

如果接下来，我想通过

向所有连接的人发送消息

socket.join(user_id);

当我使用时：

socket.on('message', function (data) {

    socket.broadcast.to(data.room).emit('recieve',data.message); //emit to 'room' except this socket

});

此会议室中的其他用户未收到该消息;但如果我使用：

socket.join(user_id);`,when i use :

    socket.on('message', function (data) {

    socket.broadcast.emit('recieve',data.message);

});

所有用户都会收到该消息。为什么房间对我不起作用？我认为代码很好！

坦克的

Answer 1

socket.on('message', function (data) {
        /*considering data.room is the correct room name you want to send message to */
        io.sockets.in(data.room).emit('recieve', data.message) //will send event to everybody in the room while 
        socket.broadcast.to(data.room).emit('recieve', data.message) //will broadcast to all sockets in the given room, except to the socket which called it
        /* Also socket.broadcast.emit will send to every connected socket except to socket which called it */
    });

我猜你需要的是io.sockets.in

socket.io创建动态空间

1 个答案: