我想在我的应用程序中实现进度监视器对话框。功能是将大文件/文件夹从一个位置复制到
另一个位置winthin Windows。如果我们在窗口内复制和粘贴,可能需要大约7-10分钟。
当我们通过eclipse rcp进度监视器对话框实现时,我们如何计算完成任务的总时间?因为对于较小的文件,它可能花费的时间非常少,而对于较大的文件则需要很长的时间。那么TOTAL_TIME = 10000.
对她的硬c有什么好处呢?
一旦工作完成,我们可以说它需要大约7或8分钟。这是我在阅读以下代码时遇到的困惑。
我会根据文件大小算法复制。
我得到了一个示例,总时间被称为TOTAL_TIME = 10000.
以下是示例代码:
public void run(IProgressMonitor monitor) throws InvocationTargetException,
InterruptedException {
monitor.beginTask("Running long running operation",
indeterminate ? IProgressMonitor.UNKNOWN : TOTAL_TIME);
for (int total = 0; total < TOTAL_TIME && !monitor.isCanceled(); total += INCREMENT) {
Thread.sleep(INCREMENT);
monitor.worked(INCREMENT);
if (total == TOTAL_TIME / 2) monitor.subTask("Doing second half");
}
monitor.done();
if (monitor.isCanceled())
throw new InterruptedException("The long running operation was cancelled");
}
}
答案 0 :(得分:0)
可以使用这样的东西(这只是粗略的例子,可以通过多种方式进行改进):
FileChannel src = null;
FileChannel dest = null;
try {
src = new FileInputStream(file1).getChannel();
dest = new FileOutputStream(file2).getChannel();
int offset = 1024;
long totalSize = src.size();
long position = 0;
int numberOfIterations = (int) (totalSize / offset);
int currentIteration = 0;
monitor.beginTask("Running long running operation", numberOfIterations);
while (!monitor.isCanceled()) {
long start = System.currentTimeMillis();
dest.transferFrom(src, position, position + offset);
long end = System.currentTimeMillis();
monitor.worked(currentIteration++);
long timeElapsedPerOneIteration = (end - start) / 1000;
monitor.setTaskName("Running long running operation. Time left: "
+ ((timeElapsedPerOneIteration * numberOfIterations) - timeElapsedPerOneIteration * currentIteration)
+ " seconds.");
position += offset;
if (position >= totalSize) {
monitor.done();
break;
}
}
} catch (FileNotFoundException e) {
// hanlde
} catch (IOException e) {
// hanlde
} finally {
if (src != null) {
try {
src.close();
} catch (IOException e) {
// hanlde
}
}
if (dest != null) {
try {
dest.close();
} catch (IOException e) {
// hanlde
}
}
}