我正在尝试运行一个基本的SQL查询,其中搜索两个字符串之一:
我已经尝试过where命令,但我得到一个空输出。 这是有问题的部分:
where execution_location = ('Nightly job up' or Nightly job 'finished');
请提供帮助,提前致谢。
答案 0 :(得分:2)
改为使用IN(...)
:
where execution_location in ('Nightly job up', 'Nightly job finished');
这是比较一个子句中多个值的方法。
答案 1 :(得分:0)
您的where字符串应该是MySQL或Transact-SQL:
WHERE (execution_location = 'Nightly job up' OR execution_location = 'Nightly job finished');
答案 2 :(得分:0)
尝试:
WHERE execution_location IN ('Nightly job up, 'Nightly job finished');
或者,如果您想要的是找到以夜间作业开头的每个字符串:
WHERE execution_location LIKE 'Nightly job%'
答案 3 :(得分:0)
尝试
where execution_location in ('Nightly job up', 'Nightly job finished');
答案 4 :(得分:0)
你的表达:
('Nightly job up' or 'Nightly job finished')
...被评估为布尔表达式,结果为0(或FALSE
)(因为字符串计算为FALSE
)。
因此,您的最终WHERE
条款相当于:
... WHERE execution_location = 0
其他人已经提供了正确的语法:)