Question

我有这种值，我需要根据一些值对它们进行分组：

{
2298597={mihpayid=403993715508098532, request_id=NULL, bank_ref_num=NULL, amt=53.77, disc=0.00,   mode=CC, PG_TYPE=AXIS, card_no=512345XXXXXX2346, name_on_card=emu, udf2=0, addedon=2013-06-03 17:34:42, status=failure, unmappedstatus=failed, Merchant_UTR=NULL, Settled_At=NULL}, 
6503939={mihpayid=Not Found, status=Not Found}
}

你可以看到有两个不同的id，它们具有相似的值。所以我想根据ID对它们进行分组。

就像在Hashmap中一样，这些id可以是键，rest会成为id的值。

我该怎么做呢。

修改

id如何分割字符串并获取id and values并将其存储到散列映射Map <String, Item> tag = new HashMap <String, Item> ();中，这要归功于upog

这是我的物品类

public class Item {
    private String mihpayid;
    private String request_id;
    private String bank_ref_num;
    private String amt;
    private String disc;
    private String mode;
    private String PG_TYPE;
    private String card_no;
    private String name_on_card;
    private String udf2;
    private String addedon;
    private String status;
    private String unmappedstatus;
    private String Merchant_UTR;
    private String Settled_At;

    public String getMihpayid() {
        return mihpayid;
    }
    public void setMihpayid(String mihpayid) {
        this.mihpayid = mihpayid;
    }
    public String getRequest_id() {
        return request_id;
    }
    public void setRequest_id(String request_id) {
        this.request_id = request_id;
    }
    public String getBank_ref_num() {
        return bank_ref_num;
    }
    public void setBank_ref_num(String bank_ref_num) {
        this.bank_ref_num = bank_ref_num;
    }
    public String getAmt() {
        return amt;
    }
    public void setAmt(String amt) {
        this.amt = amt;
    }
    public String getDisc() {
        return disc;
    }
    public void setDisc(String disc) {
        this.disc = disc;
    }
    public String getMode() {
        return mode;
    }
    public void setMode(String mode) {
        this.mode = mode;
    }
    public String getPG_TYPE() {
        return PG_TYPE;
    }
    public void setPG_TYPE(String pG_TYPE) {
        PG_TYPE = pG_TYPE;
    }
    public String getCard_no() {
        return card_no;
    }
    public void setCard_no(String card_no) {
        this.card_no = card_no;
    }
    public String getName_on_card() {
        return name_on_card;
    }
    public void setName_on_card(String name_on_card) {
        this.name_on_card = name_on_card;
    }
    public String getUdf2() {
        return udf2;
    }
    public void setUdf2(String udf2) {
        this.udf2 = udf2;
    }
    public String getAddedon() {
        return addedon;
    }
    public void setAddedon(String addedon) {
        this.addedon = addedon;
    }
    public String getStatus() {
        return status;
    }
    public void setStatus(String status) {
        this.status = status;
    }
    public String getUnmappedstatus() {
        return unmappedstatus;
    }
    public void setUnmappedstatus(String unmappedstatus) {
        this.unmappedstatus = unmappedstatus;
    }
    public String getMerchant_UTR() {
        return Merchant_UTR;
    }
    public void setMerchant_UTR(String merchant_UTR) {
        Merchant_UTR = merchant_UTR;
    }
    public String getSettled_At() {
        return Settled_At;
    }
    public void setSettled_At(String settled_At) {
        Settled_At = settled_At;
    }
}

Answer 1

你期待像

这样的事吗？

Map <String, ArrayList<Object>> tag = new HashMap <String, ArrayList<Object>> ();

对于单个ID，您可以关联值列表

修改从字符串

获取值
int keyLength =7; String str="{2298597={mihpayid=403993715508098532, request_id=NULL, bank_ref_num=NULL, amt=53.77, disc=0.00, mode=CC, PG_TYPE=AXIS, card_no=512345XXXXXX2346, name_on_card=emu, udf2=0, addedon=2013-06-03 17:34:42, status=failure, unmappedstatus=failed, Merchant_UTR=NULL, Settled_At=NULL}, 6503939={mihpayid=Not Found, status=Not Found}}"; str= str.substring(1,str.length()-2).trim(); String[] notops = str.split("},"); for (String value: notops){ value = value.trim(); System.out.print("key: " + value.substring(0,keyLength) + "\t"); System.out.print("Value: " + value.substring((keyLength+2),value.length())); System.out.println(); }

如何为给定值分组值

1 个答案: