我使用jQuery构建了一个滑块,工作正常。这是一个快速的开发,所以没有时间添加控制器。现在很难为旋转木马修理控制器。
是否有人有解决方案或其他方法来解决此问题?
演示 http://jsfiddle.net/sweetmaanu/Pn2UB/16/
$.fx.speeds._default = 1000;
function slider(container) {
var currPg = null,
firstPg = null;
container.find('> .pg').each(function (idx, pg) {
pg = $(pg);
var o = {
testimonial: pg.find('> .testimonial'),
thumb: pg.find('> .testimonial-thumb'),
pg: pg
};
o.pg.css({
position: 'absolute',
width: '100%',
height: '100%',
});
if (idx > 0) {
o.pg.css({
opacity: 0,
'z-index': -1
});
o.testimonial.css({
'margin-left': '100%'
});
o.thumb.css({
'bottom': '-100%'
});
} else {
firstPg = o;
}
o.prev = currPg;
if (currPg) {
currPg.next = o;
}
currPg = o;
});
firstPg.prev = currPg;
currPg.next = firstPg;
currPg = firstPg;
this.advance = function advance(duration) {
console.log("advance!", this);
var dur = duration || $.fx.speeds._default;
var dur2 = Math.ceil(dur / 2);
var dh = container.height();
var dw = container.width();
var nextPg = currPg.next;
nextPg.pg.css({
opacity: 1,
'z-index': null
});
var _pg = currPg;
currPg.testimonial.stop().animate({
'margin-left': -dw
}, dur, function () {
_pg.pg.css({
opacity: 0,
'z-index': -1
});
_pg = null;
});
nextPg.testimonial.stop()
.css({
'margin-left': dw
})
.animate({
'margin-left': 0
}, dur);
currPg.thumb.stop().animate({
'bottom': -dh
}, dur2, function () {
nextPg.thumb.stop()
.css({
'bottom': -dh
})
.animate({
'bottom': 0
}, dur2);
nextPg = null;
});
currPg = nextPg;
}
}
var s = new slider($('#banner'));
function scheduleNext() {
setTimeout(function () {
s.advance();
scheduleNext();
}, 5000);
}
scheduleNext();
答案 0 :(得分:1)
对于下一个滑块,您需要:
$('#next').click(function(){
s.advance();
});
但无论如何,你必须使用参数构建通用动画方法。 检查这个例子: http://jsfiddle.net/lalatino/pjTU2/ 和 http://sorgalla.com/projects/jcarousel/examples/static_controls.html
答案 1 :(得分:1)
您只想添加一个变量方向,并在点击prev和next
时更改它var direction = 'left';
$('#next').click(function(event) {
direction = 'right';
s.advance(1000,direction);
});
$('#prev').click(function(event) {
direction = 'left';
s.advance(1000,direction);
});
然后添加一行检查方向变量
if(direction == 'left')
var dw = container.width();
else if(direction =='right')
var dw = - container.width();
else{
console.log('Wrong direction')
return;
}
不要忘记在高级功能上添加参数