Question

您好我正在使用开发使用自定义列表视图的Android应用程序，但我不断收到java.lang.ArrayIndexOutOfBoundsException错误。但我无法在代码中发现任何错误，我可能会出错。

public class MainActivity extends Activity {

    ListView lv_event;

    List<HashMap<String, String>> alist;

    String[] event_name = { "The Kampala City Festival",
            "The Awakening (Lantern Meet of Poets Recital)" };
    int[] event_img = { R.drawable.kla_festival, R.drawable.city_rooming };
    String[] event_date = { "October 6th, 2013", "October 4th, 2013" };
    String[] event_venue = { "Watoto Church, Central", "National Theatre" };
    String[] event_time = { "11:30 am", "07:00 pm" };
    String[] event_info = { "The #KampalaCityFestival will on Sunday 6th October",
             "From the creators of Broken Voices of the Revolution "
             };

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        setUI();
        setEventList();
    }

    private void setEventList() {
        // TODO Auto-generated method stub
        try {
            alist = new ArrayList<HashMap<String, String>>();
            for (int i = 0; i < 3; i++) {
                HashMap<String, String> hm = new HashMap<String, String>();
                hm.put("event_picture", Integer.toString(event_img[i]));
                hm.put("event_name", event_name[i]);
                hm.put("event_date", event_date[i]);
                hm.put("event_venue", event_venue[i]);
                hm.put("event_time", event_time[i]);
                hm.put("event_info", event_info[i]);
                alist.add(hm);
            }

            // from
            String[] from = { "event_picture", "event_name", "event_date",
                    "event_venue", "event_time", "event_info" };
            // to
            int[] to = { R.id.img_view_event, R.id.tv_event_name, R.id.tv_date,
                    R.id.tv_event_place, R.id.tv_time, R.id.tv_event_info };

            SimpleAdapter adapter = new SimpleAdapter(getApplicationContext(),
                    alist, R.layout.lv_custom, from, to);

            lv_event.setAdapter(adapter);
        } catch (Exception e) {
            // TODO Auto-generated catch block
            Toast.makeText(getApplicationContext(), e.toString(),
                    Toast.LENGTH_LONG).show();
        }

    }

    private void setUI() {
        // TODO Auto-generated method stub
        lv_event = (ListView) findViewById(R.id.lv_event);
    }

Answer 1

查看所有数组，for需要更改

for (int i = 0; i < 2; i++) { // since there are only 2 elements in all your arrays.

数组的索引从0开始。因此，数组中的2个元素表示元素为arr [0]和arr [1]。 arr [2]会给你ArrayIndexOutOfBoundsException。

Answer 2

您的数组长度为2，而不是3。

从

更改你的

for (int i = 0; i < 3; i++)

到

for (int i = 0; i < 2; i++)

-

array[0]; // first element
array[1]; // second element
array[2]; // out of bounds

Answer 3

你试图迭代数组三次，期望每个数组中有三个元素。

但是在这里你只定义了两个值，例如：

String[] event_name = { "The Kampala City Festival",
        "The Awakening (Lantern Meet of Poets Recital)" };

这可能是您获得ArrayIndexOutOfBoundsException

的原因

因此，如果您希望在数组中只有2个元素，或者将一个元素添加到只有2个值的数组中，请尝试将i < 3更改为i < 2。

Answer 4

在类开头声明的数组只包含两个元素。然而，循环将尝试访问第三个元素。只需调整循环中的防护装置即可。

for (int i = 0; i < 2; i++) {
    HashMap<String, String> hm = new HashMap<String, String>();
    hm.put("event_picture", Integer.toString(event_img[i]));
    hm.put("event_name", event_name[i]);
    hm.put("event_date", event_date[i]);
    hm.put("event_venue", event_venue[i]);
    hm.put("event_time", event_time[i]);
    hm.put("event_info", event_info[i]);
    alist.add(hm);
}

Answer 5

试试这个，

for (int i = 0; i < 3; i++) {
        HashMap<String, String> hm = new HashMap<String, String>();
        hm.put("event_picture", Integer.toString(event_img[i]));
        hm.put("event_name", event_name[i]);
        hm.put("event_date", event_date[i]);
        hm.put("event_venue", event_venue[i]);
        hm.put("event_time", event_time[i]);
        hm.put("event_info", event_info[i]);
        alist.add(hm);
  }

更改此代码而非代码

   for (int i = 0; i < 2; i++) {
        HashMap<String, String> hm = new HashMap<String, String>();
        hm.put("event_picture", Integer.toString(event_img[i]));
        hm.put("event_name", event_name[i]);
        hm.put("event_date", event_date[i]);
        hm.put("event_venue", event_venue[i]);
        hm.put("event_time", event_time[i]);
        hm.put("event_info", event_info[i]);
        alist.add(hm);
  }

Answer 6

只需更改

for (int i = 0; i < 3; i++)至for (int i = 0; i < 2; i++)

或

for (int i = 0; i < event_name.length; i++)就是这样

Answer 7

使用foreach来避免这种异常。

新的foreach：

for (int i = 0; objectArray.Length()>i; i++) {
    objectArray[i].doStuff();
}

旧的foreach：

size()

也许你必须对数组的长度使用不同的方法，例如spinner1 = (Spinner)rootView.findViewById(R.id.spinner1); ...

我怎样才能解决java.lang.ArrayIndexOutOfBoundsException错误

7 个答案: