Question

我发布了一个类似的问题，但没有得到我需要的答案我有以下sql代码，它在ac＃app中构建...这段代码工作正常，除非日期范围大于1个工作周。我需要编辑代码，这样当CSIAchieved日期进入下一个工作周时，它就是SLA的“外部”。

当实现日期与目标日期在同一周内时，它在SLA内部。

if (CSILOSDate.Length > 0) {
  sql += CSILOSDate + " as [CSITarget], " +
         CSIActualDate + " as [CSIAcheived], " +
         "CASE WHEN " + CSILOSDate + " IS NULL OR " + CSIActualDate + 
                   " IS NULL THEN 'Incomplete' " +
               "WHEN " + CSIActualDate + " 
                      <= DATEADD(DAY, 6-DATEPART(WEEKDAY, " +
                      CSIActualDate + "), " + CSIActualDate + ") " + 
                   "THEN 'Inside' " +
               "WHEN " + CSIActualDate + " <= " + CSILOSDate + 
                   " THEN 'Inside' " +
               "ELSE 'Outside' " +
          "END AS [CSIStatus] ";
}

Answer 1

为什么不将另一个案例添加为第一个案例

"Case When DateDiff(week, '" + CSIActualDate +
      "', '" + CSILOSDate + "') > 0 Then 'Outside'" 
+  --- then the rest of the cases ...

Answer 2

首先，我建议您使用参数化查询。

另外，这一行：

WHEN CSIActualDate <= DATEADD(DAY, 6-DATEPART(WEEKDAY, CSIActualDate), CSIActualDate)
     THEN 'Inside'

实际上是：

WHEN CSIActualDate <= DATEADD(DAY, 6-DATEPART(WEEKDAY, CSILOSDate), CSILOSDate)
     THEN 'Inside'

Answer 3

if (CSILOSDate.Length > 0)
        {
            sql +=
                CSILOSDate + " as [CSITarget], " +
                CSIActualDate + " as [CSIAcheived], " +
                "CASE WHEN DATEDIFF(WEEK, " + CSILOSDate + ", " + CSIActualDate + ") > 0 Then 'Outside'" +
                "WHEN " + CSILOSDate + " IS NULL OR " + CSIActualDate + " IS NULL THEN 'Incomplete' " +
                "WHEN " + CSIActualDate + " <= DATEADD(DAY, 6-DATEPART(WEEKDAY, " + CSIActualDate + "), " + CSIActualDate + ") " +
                "THEN 'Inside' " +
                "WHEN " + CSIActualDate + " <= " + CSILOSDate + " THEN 'Inside' " +
                "END AS [CSIStatus] ";

在SQL Server中计算工作周的函数

3 个答案: