我有两次格式为“HH:MM”我想比较它们我有以下代码来获取现在的格式:
current_time = new Date();
hour = current_time.getHours();
minute = current_time.getMinutes();
if(hour<10){hour='0'+hour} if(minute<10){minute='0'+minute}
my_time = hour+':'+minute;
这段代码是为了在减去GMT差异后得到时间:
d = new Date()
var n = d.getTimezoneOffset();
var n1 = Math.abs(n);
var difference = (n1/60);
my_time = my_time - (0+difference);
现在应将my_time的值与match_time的值进行比较:
match_time = 10:00;//for example
if(my_time > match_time)
{
alert('yes');
}
else
{
alert('No');
}
如何将这些值作为字符串的时间进行比较???
答案 0 :(得分:13)
使用Date对象。 Date.setHours()允许您指定小时,分钟,秒
var currentD = new Date();
var startHappyHourD = new Date();
startHappyHourD.setHours(17,30,0); // 5.30 pm
var endHappyHourD = new Date();
endHappyHourD.setHours(18,30,0); // 6.30 pm
console.log("happy hour?")
if(currentD >= startHappyHourD && currentD < endHappyHourD ){
console.log("yes!");
}else{
console.log("no, sorry! between 5.30pm and 6.30pm");
}
答案 1 :(得分:4)
Date.parse('25/09/2013 13:31') > Date.parse('25/09/2013 9:15')
修改强>
请注意,您正在解析您不感兴趣的任意日期,它只需要在双方都相同。
答案 2 :(得分:1)
if(Date.parse('01/01/2011 10:20:45') == Date.parse('01/01/2011 5:10:10')) {
alert('same');
}else{
alert('different');
}
The 1st January is an arbitrary date, doesn't mean anything.
答案 3 :(得分:0)
如果我有足够的代表投票给@Gabo Esquivel解决方案。几天来,我一直在寻找和测试解决方案,这是唯一适合我的解决方案。
我需要一个条件语句测试,如果当前时间是0830,如果是,请做一些事情。我的if语句不起作用,所以我需要其他例子来处理。
//Business Hours: Saturday 8:30am-12pm; highlight Saturday table row.
function showSaturdayHours() {
var today = new Date();
var weekday = today.getDay();
var saturdayOpen = new Date();
saturdayOpen.setHours(8, 30, 0);
var saturdayClose = new Date();
saturdayClose.setHours(12, 0, 0);
if (weekday == 6) {
$('#saturday-row').addClass('row-blue'); //highlight table row if current day is Saturday.
if (today >= saturdayOpen && today < saturdayClose) {
document.getElementById('saturday-open').innerHTML = 'Open';
} else {
document.getElementById('saturday-open').innerHTML = 'Closed';
}
}
}
营业时间表:JSFiddle
答案 4 :(得分:0)
我们可以使用一些技巧。
var time1 = "09:30";
var time2 = "10:30";
var time1Date= new Date("01/01/2000 "+time1);
var time2Date= new Date("01/01/2000 "+time2);
if(time1Date >= time2Date ){
console.log("time1");
}else{
console.log("time2");
}
答案 5 :(得分:0)
与@Arjun Sol相似,您无需使用Date.parse,就可以从字符串本身中获取时间,创建一个新的Date对象并进行比较。
const time1 = '12:42';
const time2 = '18:30';
const getTime = time => new Date(2019, 9, 2, time.substring(0, 2), time.substring(3, 5), 0, 0);
const result = getTime(time1) < getTime(time2);
console.log('This should be true:', result);