Question

如何使用JSONObject在Java中创建如下所示的JSON对象？

{
    "employees": [
        {"firstName": "John", "lastName": "Doe"}, 
        {"firstName": "Anna", "lastName": "Smith"}, 
        {"firstName": "Peter", "lastName": "Jones"}
    ],
    "manager": [
        {"firstName": "John", "lastName": "Doe"}, 
        {"firstName": "Anna", "lastName": "Smith"}, 
        {"firstName": "Peter", "lastName": "Jones"}
    ]
}

我找到了很多例子，但不是我的JSONArray字符串。

Answer 1

以下是使用java 6开始的一些代码：

JSONObject jo = new JSONObject();
jo.put("firstName", "John");
jo.put("lastName", "Doe");

JSONArray ja = new JSONArray();
ja.put(jo);

JSONObject mainObj = new JSONObject();
mainObj.put("employees", ja);

修改：由于put vs add存在很多混淆，我将尝试解释其中的差异。在java 6 org.json.JSONArray中包含put方法，在java 7中javax.json包含add方法。

使用java 7中的构建器模式的示例如下所示：

JsonObject jo = Json.createObjectBuilder()
  .add("employees", Json.createArrayBuilder()
    .add(Json.createObjectBuilder()
      .add("firstName", "John")
      .add("lastName", "Doe")))
  .build();

Answer 2

我想你是从服务器或文件中获取这个JSON，并且你想从中创建一个JSONArray对象。

String strJSON = ""; // your string goes here
JSONArray jArray = (JSONArray) new JSONTokener(strJSON).nextValue();
// once you get the array, you may check items like
JSONOBject jObject = jArray.getJSONObject(0);

希望这会有所帮助：）

Answer 3

可以编写可重用的小方法来创建人json对象，以避免重复代码

JSONObject  getPerson(String firstName, String lastName){
   JSONObject person = new JSONObject();
   person .put("firstName", firstName);
   person .put("lastName", lastName);
   return person ;
} 

public JSONObject getJsonResponse(){

    JSONArray employees = new JSONArray();
    employees.put(getPerson("John","Doe"));
    employees.put(getPerson("Anna","Smith"));
    employees.put(getPerson("Peter","Jones"));

    JSONArray managers = new JSONArray();
    managers.put(getPerson("John","Doe"));
    managers.put(getPerson("Anna","Smith"));
    managers.put(getPerson("Peter","Jones"));

    JSONObject response= new JSONObject();
    response.put("employees", employees );
    response.put("manager", managers );
    return response;
  }

Answer 4

请尝试这个...希望对您有帮助

JSONObject jsonObj1=null;
JSONObject jsonObj2=null;
JSONArray array=new JSONArray();
JSONArray array2=new JSONArray();

jsonObj1=new JSONObject();
jsonObj2=new JSONObject();


array.put(new JSONObject().put("firstName", "John").put("lastName","Doe"))
.put(new JSONObject().put("firstName", "Anna").put("v", "Smith"))
.put(new JSONObject().put("firstName", "Peter").put("v", "Jones"));

array2.put(new JSONObject().put("firstName", "John").put("lastName","Doe"))
.put(new JSONObject().put("firstName", "Anna").put("v", "Smith"))
.put(new JSONObject().put("firstName", "Peter").put("v", "Jones"));

jsonObj1.put("employees", array);
jsonObj1.put("manager", array2);

Response response = null;
response = Response.status(Status.OK).entity(jsonObj1.toString()).build();
return response;

如何使用JSONObject在Java中创建正确的JSONArray

4 个答案: