Question

继续在java.util.Scanner.next（未知来源）的java.util.Scanner.throwFor（未知来源）获取java.util.InputMismatchException java.util.Scanner.nextInt（未知来源）java .util.Scanner.nextInt（未知来源）
文件顺序：字符串字符串int int

import java.util.Scanner; 
import java.io.*;

class PlayerStats 
{       
    public String name;   
    public String team;   
    public int games_ply; 
    public int goals_mde;
}

public class Program3
{
    public static void main(String[] args)
    {    

    PlayerStats[] players = new PlayerStats[100];
    int nPlayers;
    int opt;
    Scanner in = new Scanner (System.in
    nPlayers = loadPlayers (players);
    } 

    private static int loadPlayers (PlayerStats[] players)
    {   
        int nPlayers = 0;   
        try
        {   
        File file = new File ("/temp/Program3/Player.txt");
        Scanner inFile = new Scanner (file);
        do
        {
                players[ nPlayers ] = new PlayerStats();
            players[ nPlayers ].name = inFile.next();
            players[ nPlayers ].team = inFile.next();
            players[ nPlayers ].games_ply = inFile.nextInt();
            players[ nPlayers ].goals_mde = inFile.nextInt();
            ++nPlayers;
        } while ( players [nPlayers-1].goals_mde != 0);
    --nPlayers;
       }
       catch (IOException ioe)
       {
           System.out.print("\n\n\t\tFile access error!");
       nPlayers = 0;
       }
       return nPlayers;
    }
}

Answer 1

我猜您应该使用ObjectOutputStream将serialized玩家对象写入文件，并使用ObjectInputStream(new FileInputStream(new File(players.txt))).readObject来阅读对象，不要忘记将其投射到玩家< / p>

Answer 2

检查你的字符串是否有空格，如果是，那么你的代码将无效，因为.next()将读取空格

然后尝试这个

String line = inFile.nextLine();
String [] tokens = line.split("\s+");
players[ nPlayers ].name = tokens[0];
players[ nPlayers ].team = tokens[1];
players[ nPlayers ].games_ply = Integer.parseInt(tokens[2]);
players[ nPlayers ].goals_mde = Integer.parseInt(tokens[3]);

Java：无法加载文件记录数组

2 个答案: