在Chrome上触发键盘事件

时间:2009-12-13 18:51:36

标签: javascript google-chrome webkit

我正在尝试使用Chrome上的javascript将键盘事件发送到页面。 我有一种过去常用于Firefox的方法:

pressKey = function(key, shift) {
  var evt = document.createEvent('KeyboardEvent');
  evt.initKeyEvent("keypress", false, true, null, false, false,
                   shift, false, keyCode(key), key.charCodeAt(0));
  document.dispatchEvent(evt);
}

其中key是所需的键,keyCode将小写字母更改为高位字母,并且还调用charCodeAt()。

我的问题是Safari / Chrome上的事件没有initKeyEvent,而是initKeyboardEvent。我可以注意到的主要区别是你必须将密钥作为keyIdentifier(看起来像一个unicode字符)传递,而不是传递keycode和keychar。尽管如此,我仍然无法使其发挥作用。

我还尝试了here描述的JQuery方法但没有成功。

修改 我进一步调试了这一点,似乎Chrome上的事件确实触发了侦听器,但keyCode / charCode始终为0.我试图设置evt.keyCode或evt.charCode也没有成功。

5 个答案:

答案 0 :(得分:19)

我已将其跟踪到bug on Webkit,其中创建的事件仅包含KeyIdentifier,但没有browser source code上可见的keyCode / charCode。似乎有一个补丁正在解决这个问题。所以我想这不再是一个正确的问题......

答案 1 :(得分:11)

如果您想以正确的方式进行,可以使用DOM 键盘事件级别4 KeyboardEvent构造和属性。

在最新的浏览器中或使用DOM Keyboard Event Level 3/4 polyfill,您可以执行以下操作:

element.addEventListener(function(e){ console.log(e.key, e.char, e.keyCode) })

var e = new KeyboardEvent("keydown", {bubbles : true, cancelable : true, key : "Q", char : "Q", shiftKey : true});
element.dispatchEvent(e);

//If you need legacy property "keyCode".
// Note: In some browsers you can't overwrite "keyCode" property. (At least in Safari)
delete e.keyCode;
Object.defineProperty(e, "keyCode", {"value" : 666})

Example

"map event.key to character values of a normal QUERTY (en-US) layout" proposal demo

请注意,最新的Spec(www.w3.org/TR/DOM-Level-3-Events/)中不推荐使用 keyCode charCode 。因此Chrome无法通过 keyCode 支持实施 initKeyEvent 。但是你总是可以覆盖这个值: 更新:错误方法:

var evt = document.createEvent('KeyboardEvent');
evt.initKeyEvent("keypress", false, true, null, false, false,
               shift, false, keyCode(key), key.charCodeAt(0));
if(evt.keyCode != keyCode(key)) {
    delete evt.keyCode;
    // Note: In some browsers you can't overwrite "keyCode" property. (At least in Safari)
    Object.defineProperty(evt, "keyCode", { keyCode(key) });
}

或者您可以更新事件原型:更新:错误方法:

// Note: In some browsers you can't overwrite "keyCode" property. (At least in Safari)
var _native_keyCode_getter = Object.getOwnPropertyDescriptor(KeyboardEvent.prototype, "keyCode");
Object.defineProperty(KeyboardEvent.prototype, "keyCode", {
    "enumerable" : true,
    "configurable" : true,
    "get" : function() {
        if("__keyCode" in this)return this["__keyCode"];

        return _native_keyCode_getter.call(this);
    },
    "set" : function(newValue) {
        return this["__keyCode"] = isNaN(newValue) ? 0 : newValue;
    }
});    

<强>更新 initKeyboardEvent有各种实现。在我的KeyboardEvent polyfill中,我以某种方式检测它(gist):

var _initKeyboardEvent_type = (function( e ) {
    try {
        e.initKeyboardEvent(
            "keyup" // in DOMString typeArg
            , false // in boolean canBubbleArg
            , false // in boolean cancelableArg
            , global // in views::AbstractView viewArg
            , "+" // [test]in DOMString keyIdentifierArg | webkit event.keyIdentifier | IE9 event.key
            , 3 // [test]in unsigned long keyLocationArg | webkit event.keyIdentifier | IE9 event.location
            , true // [test]in boolean ctrlKeyArg | webkit event.shiftKey | old webkit event.ctrlKey | IE9 event.modifiersList
            , false // [test]shift | alt
            , true // [test]shift | alt
            , false // meta
            , false // altGraphKey
        );
        return ((e["keyIdentifier"] || e["key"]) == "+" && (e["keyLocation"] || e["location"]) == 3) && (
            e.ctrlKey ?
                e.altKey ? // webkit
                    1
                    :
                    3
                :
                e.shiftKey ?
                    2 // webkit
                    :
                    4 // IE9
            ) || 9 // FireFox|w3c
            ;
    }
    catch ( __e__ ) { alert("browser do not support KeyboardEvent") }
})( document.createEvent( "KeyboardEvent" ) );

var e = document.createEvent( "KeyboardEvent" );
...
if( "initKeyEvent" in e ) {//FF
    //https://developer.mozilla.org/en/DOM/event.initKeyEvent
    e.initKeyEvent( type, _bubbles, _cancelable, _view, _ctrlKey, _altKey, _shiftKey, _metaKey, _keyCode, _keyCode );
}
else if( "initKeyboardEvent" in e ) {//https://developer.mozilla.org/en/DOM/KeyboardEvent#initKeyboardEvent()
    if( _try_initKeyboardEvent ) {
        if( _initKeyboardEvent_type == 1 ) { // webkit
            //http://stackoverflow.com/a/8490774/1437207
            //https://bugs.webkit.org/show_bug.cgi?id=13368
            e.initKeyboardEvent( type, _bubbles, _cancelable, _view, _key, _location, _ctrlKey, _shiftKey, _altKey, _metaKey, _altGraphKey );
        }
        else if( _initKeyboardEvent_type == 2 ) { // old webkit
            //http://code.google.com/p/chromium/issues/detail?id=52408
            e.initKeyboardEvent( type, _bubbles, _cancelable, _view, _ctrlKey, _altKey, _shiftKey, _metaKey, _keyCode, _keyCode );
        }
        else if( _initKeyboardEvent_type == 3 ) { // webkit
            e.initKeyboardEvent( type, _bubbles, _cancelable, _view, _key, _location, _ctrlKey, _altKey, _shiftKey, _metaKey, _altGraphKey );
        }
        else if( _initKeyboardEvent_type == 4 ) { // IE9
            //http://msdn.microsoft.com/en-us/library/ie/ff975297(v=vs.85).aspx
            e.initKeyboardEvent( type, _bubbles, _cancelable, _view, _key, _location, _modifiersListArg, _repeat, _locale );
        }
        else { // FireFox|w3c
            //http://www.w3.org/TR/DOM-Level-3-Events/#events-KeyboardEvent-initKeyboardEvent
            //https://developer.mozilla.org/en/DOM/KeyboardEvent#initKeyboardEvent()
            e.initKeyboardEvent( type, _bubbles, _cancelable, _view, _char, _key, _location, _modifiersListArg, _repeat, _locale );
        }
    }
}

答案 2 :(得分:5)

我只是想把这个基本片段扔出去。它适用于Chrome,基于Paul Irish提到的黑客攻击 它使用charCode而不是keyCode(在某些情况下可能很有用),但如果您愿意,请使用keyCode。

var keyboardEvent = new KeyboardEvent('keypress', {bubbles:true}); 
Object.defineProperty(keyboardEvent, 'charCode', {get:function(){return this.charCodeVal;}}); 
keyboardEvent.charCodeVal = [your char code];
document.body.dispatchEvent(keyboardEvent);

答案 3 :(得分:2)

根据您的需要,TextEvent可能会起作用。 (它适合我的需要 - 对于chrome。这不是跨浏览器测试,但是,问题是关于chrome的。)

// get a reference to the DOM element you want to affect
var input = document.getElementsByTagName('input')[0];
// create a TextEvent
var textEvent = document.createEvent('TextEvent');
// initialize the TextEvent
textEvent.initTextEvent('textInput', true, true, null, String.fromCharCode(13)+"\r\n", 9, "en-US");
// dispatch ('fire') the TextEvent
input.dispatchEvent(textEvent);

答案 4 :(得分:2)

您可以使用createEvent('Event')而不是createEvent('KeyboardEvent')解决Webkit错误,然后分配keyCode属性。请参阅this answerthis example