对于某些人来说,这可能是显而易见的,但我无法弄清楚如何覆盖get_template_name
以便为我的form wizard
的不同步骤提供不同的模板。以下是我到目前为止的情况:
class StepOneForm(forms.Form):
color = forms.ChoiceField(choices=COLOR_CHOICES)
...
class StepTwoForm(forms.Form):
main_image = forms.ImageField()
...
class StepThreeForm(forms.Form):
condition = forms.ChoiceField(choices=CONDITION)
...
class CreateWizard(SessionWizardView):
file_storage = FileSystemStorage(location=os.path.join(settings.MEDIA_ROOT))
def done(self, form_list, **kwargs):
id = form_list[0].cleaned_data['id']
try:
thing = Thing.objects.get(pk=id)
instance = thing
except:
thing = None
instance = None
if thing and thing.user != self.request.user:
raise HttpResponseForbidden()
if not thing:
instance = Thing()
for form in form_list:
for field, value in form.cleaned_data.iteritems():
setattr(instance, field, value)
instance.user = self.request.user
instance.save()
return render_to_response('wizard-done.html', {
'form_data': [form.cleaned_data for form in form_list],})
urls.py:
url(r'^create/$', login_required(CreateWizard.as_view([StepOneForm, StepTwoForm, StepThreeForm])), name='create_thing'),
我已阅读Django文档并尝试使用其中描述的方法。在我的forms.py中:
FORMS = [("step_one", myapp.forms.StepOneForm),
("step_two", myapp.forms.StepTwoForm),
("step_three", myapp.forms.StepThreeForm)]
TEMPLATES = {"step_one": "myapp/step-one.html",
"step_two": "myapp/step-two.html",
"step_three": "myapp/step-three.html"}
class CreateWizard(SessionWizardView):
def get_template_names(self):
return [TEMPLATES[self.steps.current]]
...etc. ...
但这会返回KeyError at u'0'
。如何让表单向导为每个步骤显示不同的模板?
答案 0 :(得分:2)
django表单向导中的步骤为'0', '1', '2', ...
,因此您需要将TEMPLATES
dict更新为
TEMPLATES = {"0": "myapp/step-one.html",
"1": "myapp/step-two.html",
"2": "myapp/step-three.html"}
然后像你一样使用它get_template_names
:
class CreateWizard(SessionWizardView):
def get_template_names(self):
return [TEMPLATES[self.steps.current]]