我有一项任务是在包含
格式内容的文件中读取 June 17, 1997
July 23, 1997
September 28, 1980
September 31, 1980
Mar. 2, 1980
Apr. 2, 1980
May 3, 1980
Nov 25, 1989
Dec 25, 1989
Jan 3, 1973
我必须将每个日期存储到Date对象中。如果下一个日期晚于上一个日期,则应从两个日期创建DateRange对象。最终输出应该看起来像
Date: June 17, 1997
Date: July 23, 1997
DateRange: Date: June 17, 1997 - Date: July 23, 1997
Date: September 28, 1980
Invalid Date
Date: March 2, 1980
Date: April 2, 1980
DateRange: Date: March 2, 1980 - Date: April 2, 1980
Date: May 3, 1980
DateRange: Date: April 2, 1980 - Date: May 3, 1980
Date: November 25, 1989
DateRange: Date: May 3, 1980 - Date: November 25, 1989
Date: December 25, 1989
DateRange: Date: November 25, 1989 - Date: December 25, 1989
Date: January 3, 1973
首先,我很抱歉这么长的帖子和很多东西要阅读,但我已经解决了这个问题一段时间了,我不知道如何继续。我被困了,因为我不完全确定如何比较两个日期并将它们放入DateRange类。 我的主程序的片段包括:
Scanner in = null;
try {
in = new Scanner(new File("dates.txt"));
} catch (FileNotFoundException exception) {
System.err.println("failed to open dates.txt");
System.exit(1);
}
while (in.hasNextLine()) {
String line = in.nextLine();
Date date = new Date(line);
testDates(date);
if (testDateRange(date) < 0){
System.out.println("There's a range");
}
}
}
public static int testDateRange(Date dates){
return dates.compareTo(dates);
}
public static void testDates(Date dates){
System.out.printf("%s\n", dates.getDate());
//System.out.printf("Date: %s\n", dates.getDate());
}
}
我的日期课程包括:
public class Date implements Comparable<Date> {
private String dates;
private int year;
private int day;
private int month;
public Date(String line) {
dates = line; // initialize date
} // end one-argument Grades constructor
public String getDate() {
dates = dates.replace(".", "");
dates = dates.replace(",", "");
StringTokenizer st = new StringTokenizer(dates);
String initMonth = st.nextToken();
String initDay = st.nextToken();
String initYear = st.nextToken();
Integer day = Integer.parseInt(initDay);
Integer year = Integer.parseInt(initYear);
String month = initMonth.substring(0,3);
int numMonth = 0;
int maxDays = 0;
String Month = null;
switch (month){
case "Jan":
numMonth = 1;
maxDays = 31;
Month = "January";
break;
case "Feb":
numMonth = 2;
maxDays = 29;
Month = "February";
break;
case "Mar":
numMonth = 3;
maxDays = 31;
Month = "March";
break;
case "Apr":
numMonth = 4;
maxDays = 30;
Month = "April";
break;
case "May":
numMonth = 5;
maxDays = 31;
Month = "May";
break;
case "Jun":
numMonth = 6;
maxDays = 30;
Month = "June";
break;
case "Jul":
numMonth = 7;
maxDays = 31;
Month = "July";
break;
case "Aug":
numMonth = 8;
maxDays = 31;
Month = "August";
break;
case "Sep":
numMonth = 9;
maxDays = 30;
Month = "September";
break;
case "Oct":
numMonth = 10;
maxDays = 31;
Month = "October";
break;
case "Nov":
numMonth = 11;
maxDays = 30;
Month = "November";
break;
case "Dec":
numMonth = 12;
maxDays = 31;
Month = "Decemeber";
break;
default:
break;
}
if(maxDays < day){
dates = ("Invalid Date");
}else{
dates = ("Date: " + Month + " " + day + ", " + year);
}
return dates;
}
public int compareTo (Date other) {
int result = year - other.year;
if (result == 0)
{
result = month - other.month;
if (result == 0)
{
result = day - other.day;
}
}
if (result > 0) return 1;
else if (result < 0) return -1;
else return 0;
}
}
我关注的是Date类,我需要比较两个日期。在我的compareTo()方法中,我知道它总是会返回0,因为我没有正确实现它。我只是对如何实现这个compareTo()方法感到困惑,实际上将第一个日期与第二个日期进行比较,第二个日期与第三个日期进行比较,依此类推。我目前没有DateRange类,因为我无法测试两个日期以查看它们是否有范围。
答案 0 :(得分:5)
您可以尝试使用SimpleDateFormat课程。它将简化您的问题。
例如,您可以将字符串格式的日期转换为日期格式,如下所示。
String str = "June 17, 1997";
SimpleDateFormat sdf = new SimpleDateFormat("MMMM dd, yyyy", Locale.ENGLISH);
Date date = sdf.parse(str);
然后,为了比较日期,您可以使用before(date)或after(date)方法。
date.before(date2);
date.after(date2);
答案 1 :(得分:0)
类似的东西:
Date former = null;
Date latter = null;
DateRange range = null;
while(in.hasNextLine()) {
latter = readNextDate(in);
if(isLatterLarger(former, latter)) {
range = getDateRange(former, latter);
doSomethingWithRange(range);
}
former = latter;
}