Question

我有这个甜蜜的方法来验证用户，但我无法弄清楚如何获取请求的状态代码。当我NSLog(@"%@", response);时，我可以清楚地看到它存在，但是我找不到任何方法可以将它拉出来。是否有方法或者我必须以某种方式解析它？

- (BOOL)authenticateUserWithEmail:(NSString *)email password:(NSString *)password
{
    NSURL *url = [[NSURL alloc] initWithString:[NSString stringWithFormat:
                                         @"%@/users/sign_in.json?user[email]=%@&user[password]=%@&user[remember_me]=true",
                                         LURL,
                                         email,
                                         password]];
    NSMutableURLRequest *urlRequest = [[NSMutableURLRequest alloc] initWithURL:url];
    [urlRequest setHTTPMethod:@"POST"];
    NSURLResponse *response;
    NSError *error;
    NSData *responseData = [NSURLConnection sendSynchronousRequest:urlRequest returningResponse:&response error:&error];
    NSLog(@"Response: %@", [[NSString alloc] initWithData:responseData encoding:NSASCIIStringEncoding] );
    NSLog(@"Response Meta: %@", response);
    return (error == NULL);
}

Answer 1

试试这个

NSHTTPURLResponse *HTTPResponse = (NSHTTPURLResponse *)response;
NSInteger statusCode = [HTTPResponse statusCode];

从NSURLResponse中提取数据

1 个答案: