我有以下PHP代码打印:
ID:3deep:2path:image31.jpg
ID:4deep:2path:image32.jpg
当我输入deep = 2.但是我想获得这个深度的父数组,即id = 2.无论如何,我能做到这一点吗?
注意: 我输入深度时请查看结果如下:
> Deep = 1
ID = 0
ID = 1
ID = 2
ID = 7
ID = 8
> Deep = 2
ID = 2
ID = 3
ID = 4
> Deep = 3
ID = 4
ID = 5
ID = 6
请在线查看我的代码:http://phpfiddle.org/main/code/xxn-7ay
PHP代码
$obj = '{
"images": {
"deep": "1",
"id": "0",
"path": "image1.jpg",
"image": [
{
"deep": "1",
"id": "1",
"coordinate": "(x,y),(x,y)",
"path": "image2.jpg"
},
{
"deep": "1",
"id": "2",
"coordinate": "(x,y),(x,y)",
"path": "image3.jpg",
"image": [
{
"deep": "2",
"id": "3",
"coordinate": "(x,y),(x,y)",
"path": "image31.jpg"
},
{
"deep": "2",
"id": "4",
"coordinate": "(x,y),(x,y)",
"path": "image32.jpg",
"image": [
{
"deep": "3",
"id": "5",
"coordinate": "(x,y),(x,y)",
"path": "image321.jpg"
},
{
"deep": "3",
"id": "6",
"coordinate": "(x,y),(x,y)",
"path": "image322.jpg"
}
]
}
]
},
{
"deep": "1",
"id": "7",
"coordinate": "(x,y),(x,y)",
"path": "image4.jpg"
},
{
"deep": "1",
"id": "8",
"coordinate": "(x,y),(x,y)",
"path": "image5.jpg"
}
]
}
}';
$objArray = json_decode($obj,true);
$deep = 2;
$arr = all($objArray['images'], $deep);
display($arr);
function all($a, $d){
$temp = array();
if(is_array($a)){
foreach($a as $v){
all($v, $d);
}
if(isset($a['deep']) && $d == $a['deep']){
$temp['id'] = $a['id'];
$temp['deep'] = $a['deep'];
$temp['path'] = $a['path'];
$s =
'id:'.$a['id'].
'deep:'.$a['deep'].
'path:'.$a['path'];
display($s);
}
}
return ;
}
function display($a){
echo "<pre>";
print_r($a);
echo "</pre>";
}
答案 0 :(得分:1)
我想知道你想要什么,但我改变了你的代码以便以更好的方式进行过滤,并为每个parent
添加了$image
密钥,以便您可以在之后引用它。
您可以设置$deep = null
参数,只需将parent
添加到image
,而不是过滤。
我希望你不介意我改变了代码风格,更容易阅读(希望:D) 这是phpfiddle中的代码:http://phpfiddle.org/main/code/8q0-c43
<?php
$obj = '{
"images": {
"deep": "1",
"id": "0",
"path": "image1.jpg",
"image": [
{
"deep": "1",
"id": "1",
"coordinate": "(x,y),(x,y)",
"path": "image2.jpg"
},
{
"deep": "1",
"id": "2",
"coordinate": "(x,y),(x,y)",
"path": "image3.jpg",
"image": [
{
"deep": "2",
"id": "3",
"coordinate": "(x,y),(x,y)",
"path": "image31.jpg"
},
{
"deep": "2",
"id": "4",
"coordinate": "(x,y),(x,y)",
"path": "image32.jpg",
"image": [
{
"deep": "3",
"id": "5",
"coordinate": "(x,y),(x,y)",
"path": "image321.jpg"
},
{
"deep": "3",
"id": "6",
"coordinate": "(x,y),(x,y)",
"path": "image322.jpg"
}
]
}
]
},
{
"deep": "1",
"id": "7",
"coordinate": "(x,y),(x,y)",
"path": "image4.jpg"
},
{
"deep": "1",
"id": "8",
"coordinate": "(x,y),(x,y)",
"path": "image5.jpg"
}
]
}
}';
$objArray = json_decode($obj, true);
function filter_deep(array $input, $deep = null, $parent = null) {
// store $results so we can return it
$result = array();
// loop over the $input
foreach ($input as $image) {
// set the parent passed alogn
$image['parent'] = $parent;
// add $image to $result if 'deep' == $deep
if ($deep === null || $image['deep'] == $deep) {
$result[] = $image;
}
// if the $image contains more child images recursively run this function again
// and merge the result with what we already have
if (isset($image['image']) && is_array($image['image'])) {
$result = array_merge($result, filter_deep($image['image'], $deep, $image));
}
}
return $result;
}
function display_image($image) {
return "id:{$image['id']} deep:{$image['deep']} path:{$image['path']} parent_id:{$image['parent']['id']} <br />\n";
}
// loop over the images that have deep == 2 and display them
foreach (filter_deep(array($objArray['images']), 2) as $image) {
echo display_image($image);
}
?>