SQL SERVER计算ID的值

时间:2013-09-19 08:23:47

标签: count distinct grouping

我正在尝试为每个C.ID获得B.ID的计数。

到目前为止,我得到以下内容:

enter image description here

Select
C.ID,
COUNT(Distinct B.ID)AS 'Total bookings'

FROM Client C

inner join Booking B on B.ClientID=C.ID

Where ClientID = '594861'

Group by C.ID

1 个答案:

答案 0 :(得分:0)

问题出在我的小组旁边!

Select
C.ID,
COUNT(Distinct B.ID)AS 'Total bookings'

FROM Client C

inner join Booking B on B.ClientID=C.ID

Where ClientID = '594861'

Group by C.ID