我正在尝试为每个C.ID获得B.ID的计数。
到目前为止,我得到以下内容:
Select
C.ID,
COUNT(Distinct B.ID)AS 'Total bookings'
FROM Client C
inner join Booking B on B.ClientID=C.ID
Where ClientID = '594861'
Group by C.ID
答案 0 :(得分:0)
问题出在我的小组旁边!
Select
C.ID,
COUNT(Distinct B.ID)AS 'Total bookings'
FROM Client C
inner join Booking B on B.ClientID=C.ID
Where ClientID = '594861'
Group by C.ID