Question

考虑代码：

public interface IGeneral {}
public interface ISpecific : IGeneral {}
public Func<IGeneral, String> Cast(Object specificFuncAsObject) {
      var generalFunc = specificFuncAsObject as Func<IGeneral, String>;
      Assert.IsNotNull(generalFunc); // <--- casting didn't work
      return generalFunc;
}

Func<ISpecific, String> specificFunc = specific => "Hey!";
var generalFunc = Cast(specificFunc);

有没有办法让这种铸造工作？我知道在一般情况下，IGeneral无法投放到ISpecific。但在我的特殊情况下，我希望我能做到这样的事情：

 Func<IGeneral, String> generalFunc = new Func<IGeneral, String>(general => specificFunc(general as ISpecific));

但将specificFunc作为对象并ISpecific仅通过specificFuncAsObject.GetType()输入

Answer 1

Func<T, TResult>中的

T（输入类型）是contravariant, not covariant，所以这样的事情不可能直接发生。但是，您可以执行以下操作：

Func<ISpecific, String> specificFunc = specific => "Hey!";
Func<IGeneral, String> generalFunc = general => specificFunc((ISpecific)general);

反之亦然：

Func<IGeneral, String> generalFunc = general => "Hey!";
Func<ISpecific, String> specificFunc = generalFunc;

Answer 2

我认为这是不可能的，请考虑以下情况：

class Base
{
}

class DerivedA : Base
{
}

class DerivedB : Base
{
}

使用一些方法：

string DoSomething(DerivedA myDerived)
{
}

然后，在某处你有代码：

Func<DerivedA, string> functionA = DoSomething;
// Let's assume this cast is possible...
Func<Base, string> functionBase = (Func<BaseB, string>) functionA;

// At this point, the signature of the function that functionBase is assigned to
// is actually `string DoSomething(DerivedA myDerived)`
functionB(new DerivedB());
// If the cast is allowed, then passing a DerivedB should be allowed, but this makes
// absolutely no sense because the function is expecting a DerivedA.

如果您愿意，可以使用效用函数转换为强制转换（或as运算符）：

Func<Base, string> Convert<T>(Func<T, string> function) where T : Base
{
return x => function(x as T);
}

然后执行以下操作：

Func<DerivedA, string> functionA = DoSomething;
Func<Base, string> functionBase = Convert(functionA);

如何将带有派生类型参数的委托转换为具有基类型参数的委托？

2 个答案: