将列表与列表列表合并

Question

我有一份清单清单：

[['John', 'Sergeant '], ['Jack', 'Commander '], ['Jill', 'Captain ']]

如何将其与单个列表合并，如：

['800','854','453']

最终结果如下：

[['John', 'Sergeant', '800'], ['Jack', 'Commander', '854'], ['Jill', 'Captain', '453']]

最初我试过： zip(list_with_lists,list)但数据已被混淆

Answer 1

a = [['John', 'Sergeant '], ['Jack', 'Commander '], ['Jill', 'Captain ']]
b = ['800', '854', '453']
c = [x+[y] for x,y in zip(a,b)]
print c

结果：

[['John', 'Sergeant ', '800'], ['Jack', 'Commander ', '854'], ['Jill', 'Captain ', '453']]

Answer 2

使用enumerate代替zip的解决方案：

a = [['John', 'Sergeant '], ['Jack', 'Commander '], ['Jill', 'Captain ']]
b = ['800','854','453']
c = [a[i]+[bi] for i,bi in enumerate(b)]

在这种特殊情况下，使用zip绝对是更加pythonic的解决方案。但是，有时您希望能够访问索引（是的，即使在Python中），因此了解enumerate也很有用。

Answer 3

range代替zip

a = [['John', 'Sergeant '], ['Jack', 'Commander '], ['Jill', 'Captain ']]
b = ['800','854','453']
c = [a[x]+[b[x]] for x in range(len(b))]
print c

或更新原始列表：

[a[x].append(b[x]) for x in range(3)]