我想定义一个由不同类型组成的数组类型,例如String
,Integer
,Boolean
,Double
等,但没有对象,结构,或任何性质的东西。然后我想将此类型用作函数参数,例如......
type
TMyArray = array of ...?...;
function GetSomething(const Input: TMyArray): String;
var
X: Integer;
begin
for X:= 0 to Length(Input) - 1 do begin
//Identify type and handle accordingly...
//Serialize data for the result...
end;
end;
并像......一样使用它。
Variable:= GetSomething(['some string', 123, 'something else', 12.3, false]);
然后,如何在迭代这样的数组时确定每个元素的类型?
我很确定这是可能的,但甚至不知道要搜索什么术语。我该怎么做?
我是否必须将其定义为Variants数组?或者有没有办法准确定义数组接受哪些类型?
修改
不要改变任何问题,但在RRUZ的回答之后,我发现an intriguing article关于以不同的方式做这件事时的表现......
答案 0 :(得分:12)
如果你的Delphi版本支持RTTI,你可以使用TValue
和Kind
属性的数组。
{$APPTYPE CONSOLE}
uses
System.TypInfo,
System.Rtti,
System.SysUtils;
function GetSomething(const Input: array of TValue): String;
var
X: Integer;
LValue : TValue;
begin
for LValue in Input do begin
case LValue.Kind of
tkUnknown: Writeln('Unknown');
tkInteger: Writeln(Format('The Kind of the element is Integer and the value is %d',[LValue.AsInteger]));
tkChar: Writeln('Char');
tkEnumeration: if LValue.TypeInfo=TypeInfo(Boolean) then Writeln(Format('The Kind of the element is Boolean and the value is %s',[BoolToStr(LValue.AsBoolean, True)]));
tkFloat: Writeln(Format('The Kind of the element is Float and the value is %n',[LValue.AsExtended]));
tkString: Writeln('String');
tkSet: Writeln('Set');
tkClass: Writeln('Class');
tkMethod:Writeln('method');
tkWChar: Writeln('WChar');
tkLString: Writeln('String');
tkWString: Writeln('String');
tkVariant: Writeln('Variant');
tkArray: Writeln('Array');
tkRecord: Writeln('Record');
tkInterface: Writeln('Interface');
tkInt64: Writeln('Int64');
tkDynArray: Writeln('DynArray');
tkUString: Writeln(Format('The Kind of the element is String and the value is %s',[LValue.AsString]));
tkClassRef: Writeln('Class Ref');
tkPointer: Writeln('Pointer');
tkProcedure: Writeln('procedure');
end;
end;
end;
begin
try
GetSomething(['some string', 123, 'something else', 12.3, false]);
except
on E: Exception do
Writeln(E.ClassName, ': ', E.Message);
end;
Readln;
end.
另一种选择是使用array of const
{$APPTYPE CONSOLE}
uses
SysUtils;
procedure GetSomething(const Input: array of const);
var
LIndex: Integer;
begin
for LIndex := Low(Input) to High(Input) do
begin
case Input[LIndex].VType of
vtWideString: Writeln('WideString = ''', WideString(Input[LIndex].VWideChar), '''');
vtInt64: Writeln('Int64 = ', Input[LIndex].VInt64^);
vtCurrency: Writeln('Currency = ', CurrToStr(Input[LIndex].VCurrency^));
vtInteger: Writeln('Integer = ', Input[LIndex].VInteger);
vtBoolean: Writeln('Boolean = ', BoolToStr(Input[LIndex].VBoolean, True));
vtChar: Writeln('Char = ''', Input[LIndex].VChar, '''');
vtExtended: Writeln('Extended = ', FloatToStr(Input[LIndex].VExtended^));
vtString: Writeln('ShortString = ''', Input[LIndex].VString^, '''');
vtPChar: Writeln('PChar = ''', Input[LIndex].VPChar, '''');
vtAnsiString: Writeln('AnsiString = ''', Ansistring(Input[LIndex].VAnsiString), '''');
vtWideChar: Writeln('WideChar = ''', Input[LIndex].VWideChar, '''');
vtPWideChar: Writeln('PWideChar = ''', Input[LIndex].VPWideChar, '''');
vtUnicodeString : Writeln('UnicodeString = ''', string(Input[LIndex].VUnicodeString), '''');
else
Writeln('Unsupported');
end;
end;
end;
begin
try
GetSomething(['some string', 123, 'something else', 12.3, false]);
except
on E: Exception do
Writeln(E.ClassName, ': ', E.Message);
end;
Readln;
end.
答案 1 :(得分:2)
奇怪的是,还没有人提到变体记录,这几十年来一直是Pascal的特色:
type
TVarRecType = (vrtInteger, vrtDouble {other types go here});
TVarRec = record
Field1: string; { can be omitted }
case RecType: TVarRecType of
vrtInteger:
IntValue: integer;
vrtDouble:
DblValue: double;
{ other cases go here }
end;
var
VarRec: TVarRecType;
begin
VarRec.Field1 := 'This is an example.';
VarRec.RecType := vrtInteger;
VarRec.IntValue := 4711;
{...}
VarRec.RecType := wrtDouble;
VarRec.DblValue := Pi;
{...}
end;
{ Oops, forgot the array part }
type
TVarRecArr = array[1..15] of TVarRec;
var
VarRecArr: TVarRecArr;
begin
VarRecArr[1].Field1 := 'This is the first record';
VarRecArr[1].RecType := wrtInteger;
VarRecArr[1].IntValue := 1;
{...}
end;
答案 2 :(得分:1)
阵列是同质的。正如documentation所说:
数组表示相同类型的元素的索引集合(称为基本类型)。
因此,您只能通过可以容纳不同类型数据的基本类型来实现您的目标。这种数据类型称为variant data type。
在Delphi中,变体数据类型有很多种可能性。有值得尊敬的COM Variant
类型。该块上有一个新的孩子TValue
,它被添加以支持新式RTTI。还有很多第三方选择。通常,这些第三方选项可用于支持持久性框架。
答案 3 :(得分:0)
由于用作参数,您可以使用array of const
构造。
也称为变量开放数组参数。 More on my answer on this other question
它的工作方式与所需的不同类型数组相同。 Delphi docwiki documentation on that theme