Question

我有两个字符串数组名str_arr1 []，str_arr2 []。两个数组具有相同或不同的值。

str_arr1[] = { "one", "two", "three","four","Doctor","Engineer","Driver" };
str_arr2[] = { "one", "Doctor","Engineer" };

通常str_arr1 []的记录与str_arr2 []相比更多。我想检查str_arr1 []是否有str_arr2 []。如果它是真的意味着返回true。否则返回false。

Answer 1

bool contains = !str_arr2.Except(str_arr1).Any();

Answer 2

function compareArrays(arr1, arr2) {
  if (arr1.length != arr2.length) {
    return false;
  }

  return arr1.sort().join() == arr2.sort().join();
}
var arr1 = ["one", "two", "three","four","Doctor","Engineer","Driver" ];
var arr2 = ["one", "Doctor","Engineer"];

    console.log(compareArrays(arr1,arr2));

Answer 3

请使用此

static bool ArraysEqual<T>(T[] a1, T[] a2)
{
    if (ReferenceEquals(a1,a2))
        return true;

    if (a1 == null || a2 == null)
        return false;

    if (a1.Length != a2.Length)
        return false;

    EqualityComparer<T> comparer = EqualityComparer<T>.Default;
    for (int i = 0; i < a1.Length; i++)
    {
        if (!comparer.Equals(a1[i], a2[i])) return false;
    }
    return true;
}

Answer 4

bool result=str_arr2.Any(x=>!str_arr1.Contains(x));

Answer 5

var str_arr1 = new string[] { "one", "two", "three", "four", "Doctor", "Engineer", "Driver" };
        var str_arr2 = new string[] { "one", "Doctor", "Engineer" };

        return str_arr1.Intersect(str_arr2).Count() == str_arr2.Length;

Answer 6

var inter = str_arr1.Intersect( str_arr2);

foreach (var s in inter)
{
    Console.WriteLine("present" + s); // or you can return somthin
}

Answer 7

你没有清除条件。我结合了所有条件。

 string[] str_arr1 = new string[] { "one", "two", "three", "four", "Doctor", "Engineer", "Driver" };
 string[] str_arr2 = new string[] { "one", "aaaa", "yyy" };

 bool contains = !str_arr2.Except(str_arr1).Any(); // this will show true only if all the items of str_arr2 are in str_arr1 

 bool result = str_arr2.Any(x => !str_arr1.Contains(x));// this will show true if any of the items of str_arr2 are in str_arr1

使用c＃或javascript比较两个字符串数组

7 个答案: