以下是我的代码的最低工作示例。
我正在尝试使用matplotlib绘制一个实时图形,通过gui从用户那里获取一些输入。为了构建gui,我使用了库easygui
然而,有一个问题: 图表在从用户处获取更新时停止构建,我希望它继续。这里有什么东西我不知道。
#!/usr/bin/env python
from easygui import *
from matplotlib.pylab import *
import numpy
import random
n = 0
fig=plt.figure()
x=list()
y=list()
plt.title("live-plot generation")
plt.xlabel('Time(s)')
plt.ylabel('Power(mw)')
plt.ion()
plt.show()
calculated=[random.random() for a in range(40)]
recorded=[random.random() for a in range(40)]
possible=[random.random() for a in range(5)]
plt.axis([0,40,0,10000])
for a in range(0, len(recorded)):
temp_y= recorded[a]
x.append(a)
y.append(temp_y)
plt.scatter(a,temp_y)
plt.draw()
msg = "Change"
title = "knob"
choices = possible
if a>9:
b = (a/10) - numpy.fix(a/10)
if b==0:
choice = choicebox(msg, title, choices)
print "change:", choice
这是easygui
的下载链接sudo python setup.py install
基于您的Linux或OS版本。使用以下link
答案 0 :(得分:0)
感谢J.F. Sebastian
import easygui
from Tkinter import Tk
from contextlib import contextmanager
@contextmanager
def tk(timeout=5):
root = Tk() # default root
root.withdraw() # remove from the screen
# destroy all widgets in `timeout` seconds
func_id = root.after(int(1000*timeout), root.quit)
try:
yield root
finally: # cleanup
root.after_cancel(func_id) # cancel callback
root.destroy()
with tk(timeout=1.5):
easygui.msgbox('message') # it blocks for at most `timeout` seconds