Question

我是Socket通信的新手，所以我可能错了，但请建议或者至少给出指示！

我正在根据http://www.csee.umbc.edu/~pmundur/courses/CMSC691C/lab5-kurose-ross.html#appendix实施RTSP服务器，查看来自http://www.java2s.com/Open-Source/Android/UnTagged/mynpr/com/webeclubbin/mynpr/RTSPserver.java.htm的类似代码

目前我正在实施对OPTIONS请求的响应。为了在第一种方法中轻松实现，我决定根据为vlc和gstreamer rtsp之间的某些实际通信所做的示例RTSP请求/响应日志对答案进行硬编码。

因此，用vlc URL -vvv记录的日志说：

Sending request: OPTIONS rtsp://localhost:8554/test RTSP/1.0
CSeq: 2
User-Agent: LibVLC/2.0.8 (LIVE555 Streaming Media v2013.04.30)


Received 183 new bytes of response data.
Received a complete OPTIONS response:
RTSP/1.0 200 OK
CSeq: 2
Public: OPTIONS, DESCRIBE, GET_PARAMETER, PAUSE, PLAY, SETUP, SET_PARAMETER, TEARDOWN
Server: GStreamer RTSP server
Date: Tue, 10 Sep 2013 19:56:53 GMT


Sending request: DESCRIBE rtsp://localhost:8554/test RTSP/1.0
CSeq: 3
User-Agent: LibVLC/2.0.8 (LIVE555 Streaming Media v2013.04.30)
Accept: application/sdp

即。

RTSP/1.0 200 OK
CSeq: 2
Public: OPTIONS, DESCRIBE, GET_PARAMETER, PAUSE, PLAY, SETUP, SET_PARAMETER, TEARDOWN
Server: GStreamer RTSP server
Date: Tue, 10 Sep 2013 19:56:53 GMT

部分是183字节长度

根据示例我正在写缓冲区：

 try{
        System.out.println("S -> C");
        System.out.println("RTSP/1.0 200 OK");
        System.out.println("CSeq: "+RTSPSeqNb);
        //System.out.println("Session: "+RTSP_ID);
        if (responceType==OPTIONS) {System.out.println("Public: OPTIONS, DESCRIBE, GET_PARAMETER, PAUSE, PLAY, SETUP, SET_PARAMETER, TEARDOWN");};
        if (responceType==OPTIONS) {System.out.println("Server: GStreamer RTSP server");                                                        };
        if (responceType==OPTIONS) {System.out.println("Date: Tue, 10 Sep 2013 19:56:53 GMT");};
        RTSPBufferedWriter.write("RTSP/1.0 200 OK"+CRLF);
        RTSPBufferedWriter.write("CSeq: "+RTSPSeqNb+CRLF);
        //RTSPBufferedWriter.write("Session: "+RTSP_ID+CRLF);
        if (responceType==OPTIONS) {RTSPBufferedWriter.write("Public: OPTIONS, DESCRIBE, GET_PARAMETER, PAUSE, PLAY, SETUP, SET_PARAMETER, TEARDOWN"+CRLF);};
        if (responceType==OPTIONS) {RTSPBufferedWriter.write("Server: GStreamer RTSP server"+CRLF);                                                        };
        if (responceType==OPTIONS) {RTSPBufferedWriter.write("Date: Tue, 10 Sep 2013 19:56:53 GMT"+CRLF);            };
        RTSPBufferedWriter.write("Session: "+RTSP_ID+"\r"+CRLF);
        RTSPBufferedWriter.flush();

        //RTSPBufferedWriter.newLine();
        System.out.println("RTSP Server - Sent response to Client.");

    }
    catch(IOException ex)
    {
        System.out.println("Exception caught: "+ex.getStackTrace());
        //    System.exit(0);
    }

并且vlc日志说

Opening connection to 127.0.0.1, port 6666...
...remote connection opened
Sending request: OPTIONS rtsp://127.0.0.1:6666/autostream.mjpg RTSP/1.0
CSeq: 2
User-Agent: LibVLC/2.0.8 (LIVE555 Streaming Media v2013.04.30)


Received 193 new bytes of response data.
[0x7fd01c001178] live555 demux debug: connection timeout
[0x7fd01c001178] live555 demux error: Failed to connect with rtsp://127.0.0.1:6666/autostream.mjpg

CRLF为'\ n'。在我用

尝试CRLF =“\ r \ n”（并且最后一行没有+“\ r”+）之前

Received 198 new bytes of response data.

那么，那里有什么问题？ vlc在等什么？为什么示例中的默认分隔符不起作用？

Answer 1

在我将它们发布到stackoverflow之后，我总是找到问题的答案...

DOUBLE CRLF应该位于通常的RTSP协议的最后一个标头之后，而不是示例中使用的自定义标头。

java通信vlc的缓冲问题

1 个答案: