function getProject(){
var postData = {
'project' : proj_id
};
//console.log(postData);
var site_url = "<?php echo site_url('/'); ?>";
$.ajax({
type: "POST",
url: site_url + "maincontroller/project",
data: postData, //assign the var here
success: function(msg) {
$("#project").html(msg);
getSubProject();
}
});
假设这是一个函数现在我想对AJAX响应应用一个条件,响应id为<div id="project"></div>
。如果响应成功则生成此div,否则不生成。有人可以帮帮我吗?
答案 0 :(得分:4)
<强>替换
$("#project")=.html(msg);
。通过
$("#project").html(msg);
答案 1 :(得分:0)
试试这个
success: function(msg, status){
if (status == 200) {// ok
$("#project").html(msg);
getSubProject();
}
}