C,stat()的麻烦

时间:2013-09-09 05:14:24

标签: c stat

我之前从未使用过stat(),也不确定会出现什么问题。

我有一个服务器程序,它接受GET请求并解析文件路径。我还在发送GET请求的同一目录中有一个客户端程序。服务器程序正在获取GET请求并正确解析文件路径。两个程序所在目录的路径为:~/asimes2/hw2/

如果我有客户端程序发送:GET /Makefile HTTP/1.0\r\n\r\n

然后服务器程序收到同样的事情。我有两个printf()来确认我正确解析文件路径并查看完整路径。它输出:

File path = '/Makefile'
Full path = '~/asimes2/hw2/Makefile'
NOT FOUND!
Makefile中确实存在

~/asimes/hw2。这是代码:

// Alex: Parse the PATH from the GET request using httpGet
char* filePath, * pathStart = strchr(httpGet, '/');
if (pathStart != NULL) {
    // Alex: Increment to the first '/'
    httpGet += (int)(pathStart-httpGet);

    // Alex: Assuming " HTTP" is not a part of the PATH, this finds the end of the PATH
    char* pathEnd = strstr(httpGet, " HTTP");
    if (pathEnd != NULL) {
        int endLoc = (int)(pathEnd-httpGet);
        filePath = (char*)malloc((endLoc+1)*sizeof(char));
        strncpy(filePath, httpGet, endLoc);
        filePath[endLoc] = '\0';
    }
    else errorMessageExit("The GET request was not formatted as expected");
}
else errorMessageExit("The GET request was not formatted as expected");
printf("File path = '%s'\n", filePath);

char* fullPath = (char*)malloc((14+strlen(filePath))*sizeof(char));
strcpy(fullPath, "~/asimes2/hw2");
strcat(fullPath, filePath);
printf("Full path = '%s'\n", fullPath);

struct stat fileStat;
if (stat(fullPath, &fileStat) == -1) printf("NOT FOUND!\n");
else printf("HOORAY\n");

2 个答案:

答案 0 :(得分:3)

我的回答仅解决了您的文件名问题。

shell解释了这个:~/asimes2/hw2/Makefile

使用~

传递给stat()不是有效的文件名

您应该可以使用链接~或实际主目录所在的位置替换前导/home/

试试这个:

char* fullPath = malloc((80+strlen(filePath))*sizeof(char));
strcpy(fullPath, "/home/ubuntu/asimes2/hw2");
strcat(fullPath, filePath);
printf("Full path = '%s'\n", fullPath);

答案 1 :(得分:2)

您需要输入路径名,请参阅glob(7)。您也许可以使用wordexp(3)展开~$等...

HTTP服务器通常有一些可配置的document root,可能是/var/www。然后,网址路径名/Makefile将转换为/var/www/Makefile

您应该使用某些HTTP服务器库,如libonion

你至少应该使用errno进行系统调用失败的调试,所以代码

  if (stat(fullPath, &fileStat) == -1) 
      printf("%s NOT FOUND! %s\n", fullPath, strerror(errno));

也许chroot(2)可能会让您感兴趣。并阅读Advanced Linux Programming