Question

我谷歌find doc，写了这个

find . -type f -depth 1 -Btime 1

但是，IT不起作用？我怎么能这样做？

Answer 1

-Btime 5匹配五天前创建的文件（其中4.1向上舍入为5,5.1向上舍入为6）。如果您指的是从现在到五天前创建的文件，请使用-Btime -5。

find . -type f -Btime -5 # five days ago or newer
find . -type f -Btime 5 # five days ago
find . -type f -Btime +5 # five days ago or older
find . -type f -Btime +5 -Btime -10 # between five days ago and ten days ago

同样-maxdepth 1或-mindepth 1 -maxdepth 1比-depth 1快。 -depth 1遍历目录树下的所有文件。

-atime下可以使用-Btime，-ctime，-mtime和-atime可以使用的格式：

-atime n[smhdw]
        If no units are specified, this primary evaluates to true if the difference
        between the file last access time and the time find was started, rounded up to
        the next full 24-hour period, is n 24-hour periods.

        If units are specified, this primary evaluates to true if the difference between
        the file last access time and the time find was started is exactly n units.  Pos-
        sible time units are as follows:

        s       second
        m       minute (60 seconds)
        h       hour (60 minutes)
        d       day (24 hours)
        w       week (7 days)

        Any number of units may be combined in one -atime argument, for example, ``-atime
        -1h30m''.  Units are probably only useful when used in conjunction with the + or
        - modifier.

Answer 2

您的帖子类似于this thread。无论如何，你可以拥有这样的命令。

find -newerct 'now -1 hour'

或者

BEFORE=$(( $(date '+%s') - 3600 )) ## In seconds = 1 hour.
find -type f -printf '%C@ %p\n' | while read -r TS FILE; do TS=${TS%.*}; [[ TS -ge BEFORE ]] && echo "$FILE"; done

如果您打算从修改时间开始，可以使用此

find -newermt '-1 hour'

或者

BEFORE=$(( $(date '+%s') - 3600 )) ## In seconds = 1 hour.
find -type f -printf '%T@ %p\n' | while read -r TS FILE; do TS=${TS%.*}; [[ TS -ge BEFORE ]] && echo "$FILE"; done

Answer 3

find . -type f -depth 1 -Btime -1

和“ - ”到num定义的

如何在给定目录中找到一段时间后创建的所有文件？

3 个答案: