Question

我在使用SQL Server Express 2005进行分组时遇到问题

我有一个DATETIME COLUMN，但我只想按日期对其进行分组。

这是我的SQL语句：

SELECT (u.FirstName + ' ' + u.LastName) AS [FullName],d.user_id,CONVERT(varchar,d.log_date,101) AS log_date, min(d.login_time) as LOG_IN, max(d.logout_time) as LOG_OUT, sum(d.totaltime) as TOTHrs 
FROM tbldtr d INNER JOIN tblUsers u ON d.user_id = u.User_Id
WHERE d.user_id = 'ADMIN1' and d.log_date BETWEEN '6/1/2013' AND '6/15/2013'
GROUP BY DATEADD(day, DATEDIFF(day, 0, log_date), 0),u.FirstName,u.LastName,d.user_id order by d.log_date asc

但它给了我这个错误：

列'tbldtr.log_date'在选择列表中无效，因为它不包含在聚合函数或GROUP BY中子句。

提前致谢。

Answer 1

将convert(varchar,d.log_date,101)移至group by子句：

select
    u.FirstName + ' ' + u.LastName as [FullName],
    d.user_id,
    convert(varchar, d.log_date, 101) as log_date,
    min(d.login_time) as LOG_IN,
    max(d.logout_time) as LOG_OUT,
    sum(d.totaltime) as TOTHrs 
from tbldtr d
    inner join tblUsers u on d.user_id = u.User_Id
where d.user_id = 'ADMIN1' and d.log_date between '20130601' AND '20130615'
group by
     convert(varchar, d.log_date, 101),
     u.FirstName, u.LastName, d.user_id
order by log_date asc

此外，将where中的日期更改为明确格式更为安全 - YYYYMMDD

Answer 2

使用强制转换功能，它应该像：

GROUP BY CAST(d.log_date AS DATE)

Answer 3

如果您在组中移动convert(varchar,d.log_date,101)，则结果将不正确，因为它将计算日期和时间，因此当您在同一日期有不同时间的多个条目时，它会在结果中显示两次。

试试这个会起作用

SELECT ( u.firstname + ' ' + u.lastname ) AS [FullName], 
       d.user_id, 
       CONVERT(VARCHAR, cast(d.log_date  as DATE) , 101) AS log_date, 
       Min(d.login_time)                  AS LOG_IN, 
       Max(d.logout_time)                 AS LOG_OUT, 
       Sum(d.totaltime)                   AS TOTHrs 
FROM   tbldtr d 
       INNER JOIN tblusers u 
               ON d.user_id = u.user_id 
WHERE  d.user_id = 'ADMIN1' 
       AND d.log_date BETWEEN '6/1/2013' AND '6/15/2013' 
GROUP  BY cast(d.log_date  as DATE),
          u.firstname, 
          u.lastname, 
          d.user_id 
ORDER  BY d.log_date ASC

Answer 4

尝试使用以下内容：

SELECT (u.FirstName + ' ' + u.LastName) AS [FullName],d.user_id,CONVERT(varchar,d.log_date,101) AS log_date, min(d.login_time) as LOG_IN, max(d.logout_time) as LOG_OUT, sum(d.totaltime) as TOTHrs 
FROM tbldtr d INNER JOIN tblUsers u ON d.user_id = u.User_Id
WHERE d.user_id = 'ADMIN1' and d.log_date BETWEEN '6/1/2013' AND '6/15/2013'
GROUP BY (u.FirstName + ' ' + u.LastName), d.user_id, CONVERT(varchar,d.log_date,101)
order by d.log_date asc

如何仅在列日期时间中按日期分组

4 个答案: