我在wordpress论坛上发布了这个问题,但没有点击。也许你们中的一个人可能会指出我正确的方向。
我正在为我正在制作的网站整理一个wp主题。我想让布局尽可能地与网站的其余部分匹配,并且使用wp_list_pages/categories/bookmarks/etc()
方法遇到麻烦。我仔细阅读了文档,但实际上并没有看到如何将其翻译成适合我的东西。
调用没有args的函数我得到:
<li class="pagenav">Pages
<ul>
<li class="page_item page-item-2"><a href="_site_url_/?page_id=2" title="About">About</a></li>
<li class="page_item page-item-5"><a href="_site_url_/?page_id=5" title="Parent 1">Parent 1</a>
<ul>
<li class="page_item page-item-10"><a href="_site_url_/?page_id=10" title="Child 1">Child 1</a>
<ul>
<li class="page_item page-item-26"><a href="_site_url_/?page_id=26" title="Grandchild 1">Grandchild 1</a></li>
</ul>
</li>
<li class="page_item page-item-16"><a href="_site_url_/?page_id=16" title="Child 2">Child 2</a></li>
</ul>
</li>
<li class="page_item page-item-7"><a href="_site_url_/?page_id=7" title="Parent 2">Parent 2</a>
<ul>
<li class="page_item page-item-22"><a href="_site_url_/?page_id=22" title="Child 1">Child 3</a></li>
<li class="page_item page-item-24"><a href="_site_url_/?page_id=24" title="Child 2">Child 4</a></li>
</ul>
</li>
<li class="page_item page-item-14"><a href="_site_url_/?page_id=14" title="Parent 3">Parent 3</a>
<ul>
<li class="page_item page-item-18"><a href="_site_url_/?page_id=18" title="Child 1">Child 5</a></li>
<li class="page_item page-item-20"><a href="_site_url_/?page_id=20" title="Child 2">Child 6</a></li>
</ul>
</li>
</ul>
</li>
虽然我想要更像的东西:
<div class="nav-link">Pages
<div id="Pages_children">
<div class="nav-link"><a href="_site_url_/?page_id=2" title="About">About</a></div>
<div class="nav-link"><a href="_site_url_/?page_id=5" title="Parent 1">Parent 1</a>
<div id="Parent 1_children">
<div class="nav-link"><a href="_site_url_/?page_id=10" title="Child 1">Child 1</a>
<div id="Child 1_children">
<div class="nav-link"><a href="_site_url_/?page_id=26" title="Grandchild 1">Grandchild 1</a></div>
</div>
</div>
<div class="nav-link"><a href="_site_url_/?page_id=16" title="Child 2">Child 2</a></div>
</div>
</div>
<div class="nav-link"><a href="_site_url_/?page_id=7" title="Parent 2">Parent 2</a>
<div id="Parent 2_children">
<div class="nav-link"><a href="_site_url_/?page_id=22" title="Child 1">Child 3</a></div>
<div class="nav-link"><a href="_site_url_/?page_id=24" title="Child 2">Child 4</a></div>
</div>
</div>
<div class="nav-link"><a href="_site_url_/?page_id=14" title="Parent 3">Parent 3</a>
<div id="Parent 3_children">
<div class="nav-link"><a href="_site_url_/?page_id=18" title="Child 1">Child 5</a></div>
<div class="nav-link"><a href="_site_url_/?page_id=20" title="Child 2">Child 6</a></div>
</div>
</div>
</div>
</div>
有没有办法让我用args系统实现这一目标?如果没有,我是否可以从wp_list_TYPE()
请求带有链接和标题的数组?
是否有更好的方法来做这样的事情?
答案 0 :(得分:2)
尝试查看get_posts,它会返回一个数组。然后你可以遍历数组并打印出你想要的任何内容。
例如:
<?php $posts = get_posts("numberposts=5&order=DESC&orderby=date"); ?>
<h5>Latest posts</h5>
<?php foreach($posts as $post): ?>
<?php setup_postdata($post); ?>
<div class="content">
<a class="title" href="<?php the_permalink(); ?>"><?php the_title(); ?></a>
<span style="float:right" class="date"><?php the_time(__('F jS, Y', 'inove')); ?></span>
</div>
<?php endforeach; ?>