Question

谁能告诉我我做错了什么。我想以desc顺序显示最后5行。

$pull_activity_logs = mysql_query("SELECT * FROM activity_logs WHERE ac_no = '$logined_acc' order by id desc       limit 0,5") 
or die(mysql_error());  
while($row = mysql_fetch_array( $pull_activity_logs )) {
$activity_time = $row["datetime"];
$activity = $row["activity"];
}
echo "$activity";

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Answer 1

好吧，你总是可以在 asc 顺序中选择 first 5，这将是desc顺序的最后五个，然后你可以在php中反转他们的顺序（5个值不是数组无法处理的任何值）

CODE：

$pull_activity_logs = mysql_query("SELECT * FROM activity_logs WHERE ac_no = '$logined_acc' order by id asc limit 5"); 
$temp_arr = array();
while($row = mysql_fetch_array( $pull_activity_logs )) {
  $temp_arr[] = $row; //add to end
}
$final_arr = array_reverse($temp_arr);
foreach($final_arr as $row) //this doesn't have to be named $row
  $activity_time = $row["datetime"];
  $activity = $row["activity"];
  echo "$activity";
}

编辑：

现在，当我看到它时，可能整个问题在于你的回声的位置：

$pull_activity_logs = mysql_query("SELECT * FROM activity_logs WHERE ac_no = '$logined_acc' order by id desc limit 0,5") 
or die(mysql_error());  
while($row = mysql_fetch_array( $pull_activity_logs )) {
  $activity_time = $row["datetime"];
  $activity = $row["activity"];
echo "$activity"; //this goes INSIDE the loop
}

Answer 2

您可以按升序检索前五个，然后然后使用子查询在SQL中对它们进行排序：

select al.*
from (SELECT al.*
      FROM activity_logs al
      WHERE ac_no = '$logined_acc'
      order by id asc
      limit 0, 5
     ) al
order by id desc;

显示最后5行需要帮助。 PHP，MYSQL

2 个答案: