SQL存储过程运行两个选择并返回一个值

时间:2013-08-29 10:15:58

标签: asp.net sql sql-server-2008-r2

如何修改存储过程以运行两个SQL语句

CREATE procedure [dbo].[hms_GetEmployeeSalaryRecordsByContractId]
(
@Id int
)
as
SELECT c.*
FROM  contract c
where c.emp_no =  @Id AND c.leave_date='1900-01-01 00:00:00.000' and c.main_contract=1

select * from salary s where s.contract_id = firstquery.contract_id

以上可以根据一份合同找到两份工资记录

如果找到多个工资,那么我需要做一个sum(s.salary)然后将其作为存储过程中的十进制值返回。

我到目前为止已经这样做了

 USE [pamsv83x]
GO
/****** Object:  StoredProcedure [dbo].[hms_GetEmployeeSalaryRecordsByContractId]    Script Date: 08/29/2013 10:45:05 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

Create procedure [dbo].[hms_GetEmployeeSalaryRecordsByContractEmpNo]
(
@Id int,
@sallaryresult decimal(8,2) OUTPUT
)
as
DECLARE @contract_id int
DECLARE @totalsallary decimal(8,2)
set @contract_id=(SELECT c.contract_id
FROM  contract c
where c.emp_no =  @Id AND c.leave_date='1900-01-01 00:00:00.000' and c.main_contract=1)


SELECT *,SUM(salary)
from salary s 
where s.emp_no=@contract_id
return 

修订2 -----     他们可以签订多份合同,但可以拥有多个沙龙

 Create procedure [dbo].[hms_GetEmployeeSalaryRecordsByContractEmpNo]
 (
@Id int,
@sallaryresult decimal(8,2) OUTPUT
)
as
DECLARE @contract_id int
DECLARE @totalsallary decimal(8,2)
set @contract_id=(SELECT c.contract_id
FROM  contract c
where c.emp_no =  @Id AND c.leave_date='1900-01-01 00:00:00.000')


SELECT *,SUM(salary + old_salary)
from salary s 
where s.contract_id=@contract_id
return 

1 个答案:

答案 0 :(得分:0)

加入工资联系将是更好的方式。类似的东西:

CREATE procedure [dbo].[hms_GetEmployeeSalaryRecordsByContractId]
(
@Id int
)
as
SELECT 
     c.contract_id
    ,SUM(s.salary + s.old_salary)       
FROM  
    contract c
INNER JOIN
    salary s
    ON c.contract_id = s.contract_id    
WHERE
        c.emp_no = @Id 
    AND c.leave_date = '1900-01-01 00:00:00.000' 
    AND c.main_contract = 1

GROUP BY
    c.contract_id 

上述内容将接受员工ID并通过contact_id返回汇总的工资值。