Question

我正在尝试创建一个长度为6-10个字符的密码输入，如果密码错误则会出错

低于6个字符或长于10
它没有2个数字

如果您输入错误密码3次，我会尝试制作错误消息并自动关闭。

E.G请输入密码：地狱（3个字符所以会重复）请输入密码：helloa（6个字符无数字重复）请输入密码：hell12（3个字符2个数字，所以你错了3次所以我希望它关闭）

错误：密码错误3次关闭.....

这就是我所做的

#Ask user for creation of password
iCount + 1 # Goes up by one everytime password is incorrect
for iCount in range (1,4):
    while len(sPassword) <6 or len(sPassword) >10:
        sPassword =input("Please enter a Password\n\t(Must be 6-10 Characters and  must contain 2 numbers)\n Password: ")
        if len(sPassword) >10:
            print ("Error the password must be 6 characters or more 10 characters or less ")       
            if len([x for x in sPassword if x.isdigit()]) >= 2:
                print (" Password is OK")
            else:
                    print ("Error: The password must contain atleast 2 numbers") 
        elif  iCount==3:
            print ("error")

有人可以帮我吗？

Answer 1

由于只允许三次猜测，您只需在代码中使用一个循环语句。如果你在for循环结束时运行，代码应该放弃。

def get_password():
    for password_tries in range(3):
        password = input("Enter your password: ")

        if len(password) < 6:
            print("Your password is too short (minimum of 6 characters).")

        elif len(password) > 10:
            print("Your password is too long (maximum of 10 characters).")

        elif sum(c.isdigit() for c in password) < 2:
            print("Your password does not contain enough digits (minimum 2).")

        else: # none of the previous checks was hit, so password is valid!
            return password

    print("Too many failed password entries, giving up.")
    return None # or maybe raise an exception here, instead

如果您真的不想要单独的功能，您可以使用变量来指示密码是否有效。这是上面最后几行的替代方案：

       else: # none of the previous checks was hit, so password is valid!
            password_is_valid = True
            break # stop looping

    else: # this else detects running off the end of the loop (break not called)
        print("Too many failed password entries, giving up.")
        password_is_valid = False

    # user password and password_is_valid variables here

密码输入帮助{Python}

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