如果我遇到如下情况,其中B类派生自不同命名空间中的A类,则序列化oputput无法验证产生“无效XML标记名称”的基类的标记名称。
我怎么能处理这种情况?
#include <boost/archive/xml_oarchive.hpp>
#include <boost/serialization/base_object.hpp>
namespace N {
struct A
{
friend class boost::serialization::access;
int m_a;
template<class Archive>
void serialize(Archive & ar, const unsigned int version)
{
ar & BOOST_SERIALIZATION_NVP(m_a);
}
};
}
struct B : N::A
{
friend class boost::serialization::access;
template<class Archive>
void serialize(Archive & ar, const unsigned int version)
{
ar & BOOST_SERIALIZATION_BASE_OBJECT_NVP(N::A);
}
};
int main ()
{
B b;
boost::archive::xml_oarchive ar(std::cout);
ar << BOOST_SERIALIZATION_NVP(b);
}
输出是:
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<!DOCTYPE boost_serialization>
<boost_serialization signature="serialization::archive" version="9">
<b class_id="0" tracking_level="0" version="0"terminate called after throwing an instance of 'boost::archive::xml_archive_exception'
what(): Invalid XML tag name
The program has unexpectedly finished.
答案 0 :(得分:3)
当您使用不同的命名空间时,BOOST_SERIALIZATION_BASE_OBJECT_NVP
和BOOST_SERIALIZATION_NVP
不起作用。
相反,您需要在两种情况下都使用boost::serialization::make_nvp
。