Question

我有代码一直给我一个“stringwithcontentsofurl已弃用”错误，我无法弄清楚如何解决它。该应用程序一直带我去谷歌地图，显示海洋中心0.0 lat，0.0 long。这是我现在的代码......

NSString *locationStr = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlStr]];
NSLog(@"locationstr:%@",locationStr);
NSArray *items = [locationStr componentsSeparatedByString:@","];

double lat = 0.0;
double lon = 0.0;

if([items count] >= 4 && [[items objectAtIndex:0] isEqualToString:@"200"]) {
    lat = [[items objectAtIndex:2] doubleValue];
    lon = [[items objectAtIndex:3] doubleValue];
} else {
    NSLog(@"Address, %@ not found: Error %@",addressStr, [items objectAtIndex:0]);
}
NSLog(@"latlonislatlon:%.12f,%.12f,urlstr:%@",lat,lon,urlStr);
CLLocationCoordinate2D location;
location.latitude = lat;
location.longitude = lon;

感谢您的帮助！

Answer 1

已被

取代

stringWithContentsOfURL:encoding:error:

或

stringWithContentsOfURL:usedEncoding:error:

Answer 2

因为纬度和经度已将变量设置为0.0。

Answer 3

使用此选项删除弃用警告

NSString *locationStr = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlStr] encoding:NSUTF16BigEndianStringEncoding error:nil];

同时尝试使用不同的lat，因为它们可能与你的lat long有问题

Google maps API错误：“stringwithcontentsofurl已弃用”

3 个答案: