我正在编写一个程序来显示当前时间和日期10秒。我被指示我可能只使用smallwin.inc。我编写了一个使用Irvine32.inc工作的程序,但是当我切换到只有smallwin时,我需要编写一些输出数字的程序。当我添加这些时,一个非常奇怪的行为开始发生!我使用调用“dec repTime”,它将减少2而不是1!我尝试过“sub repTime,1”,它仍然是一样的!我甚至将repTime移到eax,然后减去1,然后将eax移回repTime,它仍然减去2!
我写的程序应该运行10秒钟。由于减法2问题,它运行4秒而不是!有什么问题?!?
这是我的代码:
; this code demonstrates the usage of Windows API functions to display
; current date and time. It provides a running digital clock that updates
; itself for 10 seconds. The output is displayed starting with cursor position
; (5,5) and uses yellow foreground and blue background.
INCLUDE smallwin.inc
.data
buffer DB 256 DUP(?)
prompt BYTE "Today is: " ; strings used to format the output
slash BYTE '/'
colon BYTE ':'
space BYTE " Time: "
newLine WORD 0D0Ah
repTime DWORD 10 ; display time for 10 seconds
cursPos COORD <5,5> ; cursor coordinates
.data?
outHandle DWORD ? ; storage for console output handle
sysTimeNow SYSTEMTIME <> ; storage for system time structure
sysTimeFuture SYSTEMTIME <>
.code
WriteChar PROC
pushfd
pushad
mov buffer,al
INVOKE WriteConsole, outHandle, OFFSET buffer, 1, 0, 0
popad
popfd
ret
WriteChar ENDP
outInt PROC USES eax ebx ecx edx,
number: SDWORD ; method parameter
mov ebx, 10 ; divisor for the radix system
xor ecx, ecx ; digits counter
cmp number, 0 ; is number >= 0?
jge go ; yes - proceed
neg number ; negate the number
mov al, '-'
INVOKE WriteChar
go:
mov eax, number
puDigit:
xor edx, edx
div ebx ; get one digit
push edx ; save it for further processing
inc ecx ; update the digits counter
cmp eax, 0 ; end of processing
jne puDigit
printIT:
pop eax ; get a digit from stack
or al, 30h ; ASCII conversion
INVOKE WriteChar ; print it
loop printIT
ret
outInt ENDP
format2 PROC
LOCAL zero:BYTE
mov zero, '0'
cmp ax, 10 ; number < 10 ?
jge L
push eax ; YES - output preceeding 0
INVOKE WriteConsole, outHandle, ADDR zero, 1, 0, 0
pop eax
L: INVOKE outInt, eax ; output the number itself
ret
format2 ENDP
main PROC
INVOKE GetStdHandle, STD_OUTPUT_HANDLE
mov outHandle, eax ; get console handle for output
INVOKE SetConsoleTextAttribute, outHandle, 30 ; setup colors
INVOKE GetLocalTime, ADDR sysTimeFuture
;set Future Time to Dec 25, 2013
mov sysTimeFuture.wDay, 25
mov sysTimeFuture.wMonth, 12
mov sysTimeFuture.wYear, 2013
mov sysTimeFuture.wHour, 0
mov sysTimeFuture.wMinute, 0
mov sysTimeFuture.wSecond, 0
startLabel:
INVOKE SetConsoleCursorPosition, outHandle, cursPos
INVOKE GetLocalTime, ADDR sysTimeNow ; retrieve current date/time
INVOKE WriteConsole, outHandle, ADDR prompt,
SIZEOF prompt, 0, 0 ; output prompt
mov eax, 0
mov ax, sysTimeNow.wDay ; day of the month
call format2
INVOKE WriteConsole, outHandle, ADDR slash, 1, 0, 0 ; output '/'
mov ax, sysTimeNow.wMonth ; month number
call format2
INVOKE WriteConsole, outHandle, ADDR slash, 1, 0, 0 ; output '/'
mov ax, sysTimeNow.wYear ; print out the year
INVOKE outInt, ax
INVOKE WriteConsole, outHandle, ADDR space, SIZEOF space, 0, 0
mov ax, sysTimeNow.wHour ; output hours
call format2
INVOKE WriteConsole, outHandle, ADDR colon, 1, 0, 0 ; output ':'
mov ax, sysTimeNow.wMinute ; output minutes
call format2
INVOKE WriteConsole, outHandle, ADDR colon, 1, 0, 0 ; output ':'
mov ax, sysTimeNow.wSecond ; output seconds
call format2
INVOKE Sleep, 1000 ; wait for 1 second
dec repTime ; update the stop watch counter
jnz startLabel
INVOKE SetConsoleTextAttribute, outHandle, 15 ; reset the colors
INVOKE WriteConsole, outHandle, ADDR newLine, 2, 0, 0 ; start new line
INVOKE ExitProcess, 0
main ENDP
END main
答案 0 :(得分:0)
查看outint
的原型:
outInt PROTO number:SDWORD
预期的参数是 S 签名 DWORD - SDWORD
或者它可能是DWORD
,无所谓,看看你传递的是什么作为参数:
mov ax, sysTimeNow.wYear ; print out the year
INVOKE outInt, ax
您正在传递一个WORD
大小的注册表作为参数,并在程序中使用eax
。
将以上两行更改为:
movzx eax, sysTimeNow.wYear ; print out the year
INVOKE outInt, eax
或:
xor eax, eax
mov ax, sysTimeNow.wYear ; print out the year
INVOKE outInt, eax
将eax
的上半部分“清零”并使其正常工作。或者,您可以做的是使该过程期望WORD
大小的参数,因为这是您传递的内容,并在proc中使用ax
而不是eax
。