从PHP中检索Javascript中的JSON数组

时间:2013-08-20 21:41:58

标签: php javascript jquery ajax

我试图从PHP返回一个json编码的数组到JS,我之前做了很多次但现在我得到了一个奇怪的错误。我成功获取数据并以chrome显示数组。但是,如果我指定dataType: 'json',我无法进入AJAX成功函数。如果我删除了dataType并使用var parsed = JSON.parse(data);,它将进入成功函数,但会抛出意外的类型错误。请帮忙。

Chrome输出

[
    {
        "fullURL": "https://lh6.googleusercontent.com/--ZKG_L-SA9c/UgqECNqP4II/AAAAAAAAA2I/i5nCa3CvKqM/s912/2010raptor_firstdrive002_opt.jpg",
        "thumbURL": "https://lh6.googleusercontent.com/--ZKG_L-SA9c/UgqECNqP4II/AAAAAAAAA2I/i5nCa3CvKqM/s128-c/2010raptor_firstdrive002_opt.jpg",
        "location": "",
        "caption": "",
        "tags": "",
        "program_instance_id": "a0Ji0000001pPO6EAM"
    },
    {
        "fullURL": "https://lh3.googleusercontent.com/-kyUg7_Rul90/UgqEDIu4DhI/AAAAAAAAA2Q/WF0BAEI7smo/s912/220px-Microchip_PIC24HJ32GP202.jpg",
        "thumbURL": "https://lh3.googleusercontent.com/-kyUg7_Rul90/UgqEDIu4DhI/AAAAAAAAA2Q/WF0BAEI7smo/s128-c/220px-Microchip_PIC24HJ32GP202.jpg",
        "location": "",
        "caption": "",
        "tags": "",
        "program_instance_id": "a0Ji0000001pPO6EAM"
    }
]

PHP

$arr = array();
foreach($photoURLS as $photo)
{
$arr[] = $photo;
}

}
echo json_encode($arr);

JS

$.ajax
({
    async: "false",
    type: 'POST',
    data: {action: 'var1', albumName: 'var2'},
    dataType: 'json',
    url: '/controller/function',
        success: function(data) 
        {
        //alert($.isArray(data));
        $.each(parsed, function(i, index) {
        alert(index.fullURL);
        });
        }
 });

3 个答案:

答案 0 :(得分:1)

所以我重新编写了代码并认为这个解决方案可能适合您。

$.ajax({
  async: "false",
  type: 'POST',
  data: {
    action: 'var1',
    albumName: 'var2'
  },
  dataType: 'json',
  url: '/controller/function',
  success: function(data) {
    $.each(data, function(index, element) {
      console.log(index);
      console.log(element.fullURL);
      console.log(element);
    });
  }
});

我无法测试ajax事件但是我已经测试了你提供的每个循环的json并且接缝工作。 LINK TO FIDDLE

var data = [{
    "caption": "",
        "fullURL": "https://lh6.googleusercontent.com/--ZKG_L-SA9c/UgqECNqP4II/AAAAAAAAA2I/i5nCa3CvKqM/s912/2010raptor_firstdrive002_opt.jpg",
        "location": "",
        "program_instance_id": "a0Ji0000001pPO6EAM",
        "tags": "",
        "thumbURL": "https://lh6.googleusercontent.com/--ZKG_L-SA9c/UgqECNqP4II/AAAAAAAAA2I/i5nCa3CvKqM/s128-c/2010raptor_firstdrive002_opt.jpg"
}, {
    "caption": "",
        "fullURL": "https://lh3.googleusercontent.com/-kyUg7_Rul90/UgqEDIu4DhI/AAAAAAAAA2Q/WF0BAEI7smo/s912/220px-Microchip_PIC24HJ32GP202.jpg",
        "location": "",
        "program_instance_id": "a0Ji0000001pPO6EAM",
        "tags": "",
        "thumbURL": "https://lh3.googleusercontent.com/-kyUg7_Rul90/UgqEDIu4DhI/AAAAAAAAA2Q/WF0BAEI7smo/s128-c/220px-Microchip_PIC24HJ32GP202.jpg"
}];

$.each(data, function (index, element) {
    console.log(index);
    console.log(element.fullURL);
});

同样好消息是你的json 100%有效,所以传回的接缝是正确的。希望这有帮助

答案 1 :(得分:0)

也许您需要在响应中发送正确的HTTP标头。 见这里:https://stackoverflow.com/questions/267546/correct-http-header-for-json-file

答案 2 :(得分:0)

未定义parsed函数的变量$.each。您应该使用data代替parsed,因为datasuccess回调函数中的变量。

$.each(data, function(i, index) {
    alert(index.fullURL);
    });