这是我的代码:
import pygame, sys
from pygame.locals import *
pygame.init()
window = pygame.display.set_mode((800, 600))
pygame.display.set_caption('window')
black = (0,0,0)
white = (255, 255, 255)
logo = pygame.image.load('logo.png').convert_alpha()
clock = pygame.time.Clock()
# Sprites
m1 = pygame.image.load('m1.png').convert_alpha()
m2 = pygame.image.load('m2.png').convert_alpha()
mci = 1
x, y = 0, 0
run = True
while run:
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
if event.type == pygame.KEYDOWN:
if event.type == pygame.K_LEFT:
x -= 10
if event.type == pygame.K_RIGHT:
x += 10
if event.type == pygame.K_UP:
y -= 10
if event.type == pygame.K_DOWN:
y += 10
window.fill(white)
pygame.draw.rect(window, black,(x,y, 50, 50))
pygame.display.flip()
clock.tick(10)
一切都出现了,但是我不能用我的箭头键移动矩形,我退出之后总是出错,帮助..提前谢谢! P.S我显然是从教程中复制,但我不确定我做错了什么?
答案 0 :(得分:2)
在您解决问题时,您需要使用event.key == ...
。您可能还想观察循环的嵌套,目前您有:
while running:
for event in list_of_events:
process_event
draw_to_screen
wait_a_while
这导致另一个问题(https://stackoverflow.com/a/13866804/2372604)出现问题。您可能想要的更像是:
while running:
for event in list_of_events:
process_event
draw_to_screen
wait_a_while
您可能还想将pygame.quit(); sys.exit()
更改为run = false
,然后在该计划结束时添加pygame.quit()
。
答案 1 :(得分:0)
我写的event.type
而不是event.key
的错误。