Question

我尝试将一个针对Android的SOAP查询请求发送到w3schools服务器，在那里它将温度从摄氏度转换为华氏度，但我从服务器收到以下响应：

Server was unable to process request. 
---&gt; Data at the root level is invalid. 
Line 1, position 1.

服务员在： http://w3schools.com/webservices/tempconvert.asmx。我们可以在http://w3schools.com/webservices/tempconvert.asmx?op=CelsiusToFahrenheit找到SOAP请求消息结构。这是我的代码。

public class MainActivity extends Activity {

private static final String URL =           
           "http://www.w3schools.com/webservices/tempconvert.asmx";
TextView tv;

@Override
protected void onCreate(Bundle savedInstanceState) {
   super.onCreate(savedInstanceState);
   setContentView(R.layout.activity_main);

   HttpClient httpclient = new DefaultHttpClient();
   HttpResponse response;
   StringBuffer sb = new StringBuffer("" +
      "POST /webservices/tempconvert.asmx HTTP/1.1" +
      "Host: w3schools.com" +
      //"Content-Type: text/xml; charset=utf-8" +
      //"Content-Length: length" +
      "SOAPAction: \"http://tempuri.org/CelsiusToFahrenheit\"" +
          "<?xml version=\"1.0\" encoding=\"utf-8\"?>" +
      "<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" " +
                     "xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" " +
             "xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\">" +
     "<soap:Body>" +
       "<CelsiusToFahrenheit xmlns=\"http://tempuri.org/\">" +
           "<Celsius>24</Celsius>" +
       "</CelsiusToFahrenheit>" +
     "</soap:Body>" +
       "</soap:Envelope>");

   HttpPost request = new HttpPost(URL);
   request.setHeader("Content-Type", "application/soap+xml; charset=utf-8");

   tv = (TextView) findViewById(R.id.textView1);

   try {
     List<NameValuePair> pairs = new ArrayList<NameValuePair>();
     pairs.add(new BasicNameValuePair("myxml", sb.toString()));
     request.setEntity(new UrlEncodedFormEntity(pairs));

     response = httpclient.execute(request);
     String response_string = EntityUtils.toString(response.getEntity());
     //Here we should parse the response xml
     //But for quicker way, we will display the whole response.
     tv.setText("Temperature in Fahrenheit is: " + response_string);
     Log.v("responseString", response_string)

   } catch (UnsupportedEncodingException e) {
      e.printStackTrace();
   } catch (ClientProtocolException e) {
      e.printStackTrace();
   } catch (IOException e) {
      e.printStackTrace();
   }
    }
 }

如果你们能帮助我，我将不胜感激。谢谢！

Answer 1

您可能需要考虑使用Ksoap2。

关于特别修复这个问题，我用SoapUI做了一些测试来检查WS并用你编写请求的方式做一些测试，实际上它给出了一个错误。尝试将tempuri.org添加到信封：

  "<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" " +
                 "xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" " +
         "xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\" "+ 
         "xmlns:tem=\"http://tempuri.org/\"   >  " +

写下这样的身体：

   <soap:Body>
      <tem:CelsiusToFahrenheit>
         <tem:Celsius>30</tem:Celsius>
      </tem:CelsiusToFahrenheit>
   </soap:Body>

希望这有帮助，并考虑使用Ksoap2，真的

从Android发送SOAP请求。服务器响应：“服务器无法处理请求。”

1 个答案: