我对Google的uiautomator有相当多的经验;然而,在手机的主屏幕上添加小部件时,我似乎感到难过。现在让我们保持简单,并假设添加小部件的屏幕是空的。思考过程是打开app抽屉>点击小工具标签>找到要添加的小部件>长按并将小部件拖动到主屏幕。虽然小部件似乎不是“长时间可点击”。任何想法/建议/解决方案将不胜感激。我实施的代码如下。
@Override
protected void setUp() throws UiObjectNotFoundException {
getUiDevice().pressHome();
new UiObject(new UiSelector().className(TEXT_VIEW).description("Apps")).clickAndWaitForNewWindow();
new UiObject(new UiSelector().className(TEXT_VIEW).text("Widgets")).click();
UiScrollable widgets = new UiScrollable(new UiSelector().scrollable(true));
widgets.setAsHorizontalList();
widgets.flingToEnd(MAX_SWIPES);
UiObject widget = widgets.getChildByText(
new UiSelector().className(TEXT_VIEW).resourceId("com.android.launcher:id/widget_name"),
WIDGET_NAME
);
// Returns true
System.out.println("exists(): " + widget.exists());
// Returns false...
System.out.println("longClickable(): " + widget.isLongClickable());
widget.longClick();
// Also tried...
int startX = sonosWidget.getVisibleBounds().centerX();
int startY = sonosWidget.getVisibleBounds().centerY();
getUiDevice().drag(startX, startY, 0, 0, 3);
}
答案 0 :(得分:1)
使用Anders的想法,我设法长按小部件并将其拖到家中的某个地方,然后我在回到小部件列表之前简要地看到我的配置活动:((Kolin代码)
@Before fun setWidgetOnHome() {
mDevice = UiDevice.getInstance(InstrumentationRegistry.getInstrumentation())
val screenSize = Point(mDevice.displayWidth, mDevice.displayHeight)
val screenCenter = Point(screenSize.x / 2, screenSize.y / 2)
mDevice.pressHome()
val launcherPackage = mDevice.launcherPackageName!!
mDevice.wait(Until.hasObject(By.pkg(launcherPackage).depth(0)), LAUNCH_TIMEOUT)
// attempt long press
mDevice.swipe(arrayOf(screenCenter, screenCenter), 150)
pauseTest(2000)
mDevice.findObject(By.text("Widgets")).click()
mDevice.waitForIdle()
val y = screenSize.y / 2
var widget = mDevice.findObject(By.text("Efficio"))
var additionalSwipe = 1
while (widget == null || additionalSwipe > 0) {
mDevice.swipe(screenCenter.x, y, screenCenter.x, 0, 150)
mDevice.waitForIdle()
if (widget == null) {
widget = mDevice.findObject(By.text("Efficio"))
} else {
additionalSwipe--
}
}
val b = widget.visibleBounds
val c = Point(b.left + 150, b.bottom + 150)
val dest = Point(c.x + 250, c.y + 250)
mDevice.swipe(arrayOf(c, c, dest), 150)
}
我相信事情正在发生,但又是什么? : - /它就像一个背面被点击了
答案 1 :(得分:0)
在uiautomator Android中长按也可以使用:
执行 public boolean drag (int startX, int startY, int endX, int endY, int steps)
执行从一个坐标到另一个坐标的滑动。您可以通过指定步数来控制滑动的平滑度和速度。每个步骤的执行被限制为每步5毫秒,因此对于100步,滑动将花费大约0.5秒来完成。
参数:
startX ::起始坐标的X轴值
startY ::起始坐标的Y轴值
endX ::结束坐标的 endY ::结束坐标的 Steps ::是滑动操作的步骤数。 返回: 如果执行滑动,则为true;如果操作失败或坐标无效,则为false。 自: Android API等级18 所以给(startX,startY)=(endX,endY)。这相当于长按一次。
答案 2 :(得分:0)
感谢@geob-o-matic发布的代码。
我必须添加一些修改才能工作:
代码内联的额外说明,您可能需要更改案例中的某些值,以便通过评论。
const val TIMEOUT: Long = 5000
// WIDGET_SELECTION_AT_X: USE here true or depending
// if you have to scroll at the X or Y axis when
// navigating through widget selection screen.
const val WIDGET_SELECTION_AT_X: Boolean = true
const val WIDGET_NAME: String = "MyAppWigdetName"
@RunWith(AndroidJUnit4::class)
class WidgetAutomatorTest {
private val mDevice = UiDevice.getInstance(InstrumentationRegistry.getInstrumentation())
@Before
fun setWidgetOnHome() {
val screenSize = Point(mDevice.displayWidth, mDevice.displayHeight)
val screenCenter = Point(screenSize.x / 2, screenSize.y / 2)
// showWidgets: This a point on screen between the bottom icons
// and the widgets, its a point that has no objects on a Galaxy S5
// device with stock Launcher. Most probably you have to modify it in
// your device or use an empty homescreen and just long press at
// the center of it.
val showWidgets = Point(825, 1500)
mDevice.pressHome()
val launcherPackage = mDevice.launcherPackageName!!
mDevice.wait(Until.hasObject(By.pkg(launcherPackage).depth(0)), TIMEOUT)
// attempt long press
// Here you can use the screenCenter if you don't have any widget standing/living there!
// ie. mDevice.swipe(arrayOf(showWidgets, screenCenter), 150)
mDevice.swipe(arrayOf(showWidgets, showWidgets), 150)
// Navigate to the system's widget selector, localaize if needed.
mDevice.findObject(By.text("Widgets")).click()
var diment = screenSize.y / 2
if (WIDGET_SELECTION_AT_X) {
diment = screenSize.x / 2
}
var widget = findMyWidget(WIDGET_NAME)
while (widget == null) {
if (WIDGET_SELECTION_AT_X) {
// Swipe left to right
mDevice.swipe(diment, screenCenter.y, 0, screenCenter.y, 150)
} else {
// Swipe top to bottom
mDevice.swipe(screenCenter.x, diment, screenCenter.x, 0, 150)
}
widget = findMyWidget(WIDGET_NAME)
}
// Throw the selected widget on screen
val b = widget.visibleBounds
val c = Point(b.left + 150, b.bottom + 150)
val dest = Point(c.x + 250, c.y + 250)
mDevice.swipe(arrayOf(c, c, dest), 150)
}
private fun findMyWidget(withName: String): UiObject2? {
return mDevice.findObject(By.text(withName))
}
@Test
fun addWidget() {
// Press the button on the Widget Configuration Activity
val okButton = mDevice.findObject(UiSelector()
.text("Add widget")
.className("android.widget.Button"))
okButton.click()
// Find the just added widget
val widget = mDevice.findObject(By.descContains(WIDGET_NAME))
// Click outside the widget in order to added in the screen
mDevice.click(widget.visibleBounds.left - 150, widget.visibleBounds.top - 150)
}
}
注意。提供的示例在Galaxy S5,Android 6.0.1,1080x1920中完美运行。
答案 3 :(得分:-2)
你可以使用dragTo(相同的UI对象,步骤)
*步骤应该是> 100以确保点击足够长