Question

在Nginx中，我有一个像这样的设置：

server {
    listen   80;
    server_name  *.example.com;

    location / {
        root   /data/sites/www.example.com/widgets/public_html;
        index  index.php index.html index.htm;
        try_files $uri $uri/ /index.php?q=$uri&$args;
    }

    location ~ .php$ {
      root          /data/sites/www.examples.com/widgets/public_html;
      fastcgi_pass   127.0.0.1:9000;
      fastcgi_param  SCRIPT_FILENAME $document_root$fastcgi_script_name;
      fastcgi_index  index.php;
      include        fastcgi_params;
    }
}

如果我输入abc.example.com，它就可以了。现在在PHP中我需要读取子域。我这样得到子域名：

$url = $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];
$urlSegments = parse_url($url);
$urlHostSegments = explode('.', $urlSegments['host']);
$subdomain = $urlHostSegments[0];

问题是，它不是以 abc 作为子域返回，而是返回 * 。那么对于PHP和NGINX，我怎样才能获得带有catch all的实际子域名？

Answer 1

尝试：

array_shift(explode(".",$_SERVER['HTTP_HOST']));

Answer 2

print_r($_SERVER);

知道正确的变量。

，HTTP_HOST，当然不是SERVER_NAME

Nginx和Catch for Sub Domain with PHP

2 个答案: