如何插入一些与其id连接的值,e
UPDATE `hosting`.`invoice` SET `invoice_no` = 'wb/1420/'+'invoice_id
WHERE `invoice`.`invoice_id` != 38;
答案 0 :(得分:1)
使用mysql的concat
函数
UPDATE `hosting`.`invoice` SET `invoice_no` = CONCAT('wb/1420/', invoice_id)
WHERE `invoice`.`invoice_id` != 38;
答案 1 :(得分:0)
尝试像这样使用
$value = 'wb/1420/'.invoice_id;
UPDATE hosting.invoice SET invoice_no =$value WHERE invoice.invoice_id != 38;