Question

我在一个文件中有数据，该文件有两组值，然后是一组未指定的数组（每个中有3个子项）

例如：

('January', 2, [('curly', 30), ('larry',10), ('moe',20)])

我需要读取并呈现数据，并将数据部分重新分配给新变量。

例如：

Month: January
Section: 3 
curly has worked 30 hours 
larry has worked 10 hours 
moe has worked 20 hours

我可以得到字符串读取的前两部分，但不知道如何打破数组 - 每个文件可能有不同数量的子数组，所以需要同时做循环？

import ast 

filecontent = ast.literal_eval(filename.read())

for item in filecontent:
    month = filecontent[0]
    section = filecontent[1]

    name1 = filecontent[2] # not working
    hours1 = filecontent[3]# not working
    name2 = filecontent[4]# not working
    hours2 = filecontent[5]# not working
    # account for additional arrays somehow?

print ("month:" + month)
print ("section" + str (section))
print (str (name1) + "has worked"  + str (hours1))
print (str (name2) + "has worked"  + str (hours2))

Answer 1

您需要迭代序列中的第三个项目。

for item in filecontent:
    print 'Month %s' % item[0]
    print 'Section %d' % item[1]

    for name, hours in item[2]:
        print "%s has worked %d hours" % (name, hours)

Answer 2

您使用item迭代filecontent，但根本不使用item。我认为有一个错误。也许您应该使用item [0]而不是filecontent [0]，item [1]而不是filecontent [1]等等

Answer 3

就像贾斯汀建议的那样，你必须遍历filecontent中的第三项：即迭代文件内容[2]

Answer 4

我现在需要弄清楚如何阅读和处理数组中的其他项目。例如，奖金的新数字

filecontent = [（'January'，2，[（'curly'，30， 5 ），（'larry'，10， 5 ），（' moe'，20， 10 ）]）]

以下代码可以正常工作，并允许用户进行计算基于数据。我现在需要增加第三个数字。项目完成。

filecontent = [('January', 2, [('curly', 30), ('larry',10), ('moe',20)])]

staff = dict()

for item in filecontent:
    month = filecontent[0]
    section = filecontent[1]

    for name, hours in filecontent[2]:
        staff[name] = hours

print ("month:" + month)
print ("section: " + str (section))

print ("".join("%s has worked %s hours\n" % (name, hours) for name, hours in staff.items()))

overtime = int(input ("Enter overtime figure: "))

print ("".join("%s has now worked %s hours \n" % (name, (hours + overtime)) for name, hours in staff.items()))

我试过这个;

staff = dict()

for item in filecontent:
    month = filecontent[0]
    section = filecontent[1]

    for name, hours, bonus in filecontent[2]:
        staff[name] = hours, bonus

print ("month:" + month)
print ("section: " + str (section))

print ("".join("%s has worked %s hours with %s bonus \n" % (name, hours, bonus) for name, hours, bonus in staff.items()))

Answer 5

您可以使用字典来存储您的员工。的修改

work = [('January', 2, [('curly', 30, 5), ('larry',10, 5), ('moe',20, 10)])]

workers = dict()
month = ""
section = ""
for w in work:
    month = w[0]
    section = w[1]
    for worker, time, overtime in w[2]:
        workers[worker] = (time, overtime)
    print "Month: {0}\nSection: {1}".format(month, section)
    print "".join("%s has worked %s hours, overtime %s\n" % (worker, time[0], time[1]) for worker, time in workers.items())

打破字符串和数组向下介绍单独的项目

5 个答案: