Question

<?php
include 'dbConfig.php';
$address=mysql_real_escape_string($_POST['address']);
$pincode=mysql_real_escape_string($_POST['pincode']);
$phone=mysql_real_escape_string($_POST['phone']);
$email=mysql_real_escape_string($_POST['contactemail']);
$id=1;
$sql="UPDATE contactus SET address = '$address' , pincode = '$pincode' , phone = '$phone' , email = '$email' WEHER id='$id'";
$result=mysql_query($sql);
if (!$result)
{
    die('Error: '. mysqli_error());

}

它给出了这样的答案： -

DB initiated
Error:

问题是什么？？

Answer 1

使用正确的mysqli语法。这里有一个例子

<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

mysqli_query($con,"UPDATE Persons SET Age=36
WHERE FirstName='Peter' AND LastName='Griffin'");

mysqli_close($con);
?>

来源：http://www.w3schools.com/php/php_mysql_update.asp

并修复您的查询

 WEHER id='$id'";

通过

WHERE id='$id'"

Answer 2

$sql="UPDATE contactus SET address = '$address' , pincode = '$pincode' , phone = '$phone' , email = '$email' WEHER id='$id'";
$result=mysql_query($sql);
if (!$result)
{
    die('Error: '. mysqli_error());

}

应该是

$sql="UPDATE contactus SET address = '$address' , pincode = '$pincode' , phone = '$phone' , email = '$email' WHERE id='$id'";
$result=mysql_query($sql);
if (!$result)
{
    die('Error: '. mysql_error());

}

Answer 3

WHERE拼写错误为WEHER：

试试这个

$sql="UPDATE contactus SET address = '$address' , pincode = '$pincode' , phone = '$phone' , email = '$email' WHERE id='$id'";

Answer 4

您是否在mysql_query函数中传递了“link identifier”参数？

resource mysql_query ( string $query [, resource $link_identifier = NULL ] )

我知道这不是强制性的，但是您正在使用mysql_query执行查询，使用mysqli获取错误，dbconfig我们无法看到它。所以很难猜到。

使用php mysql更新查询不会更新数据库表条目

4 个答案: