Question

我有一个如下所示的数组：

Array
(
    [0] => Array
        (
            [id] => 1
            [firstname] => Firstname one
            [lastname] => Lastname one
        )

    [1] => Array
        (
            [id] => 2
            [firstname] => Firstname two
            [lastname] => Lastname two
        )

    [2] => Array
        (
            [id] => 3
            [firstname] => Firstname three
            [lastname] => Lastname three
        )
)

我想遍历数组并用 N / A

替换每个空格或null

我尝试了下面的代码，但没有成功：

foreach($members as $member)
{
    foreach($member as $k => $v)
    {
         if($member[$k][$v] == null || trim($member[$k][$v]) == "")
         {
                 $member[$k][$v] = "N/A";
         }
    }
}

Answer 1

我认为这就是你的目标：

$members = array(0 => array('id' => ""), 1 => array('id' => "hello"), 2 => array('name' => ""));

foreach($members as &$member)
{
   foreach($member as $k => $v)
   {
      if (empty($v)) {
           $member[$k] = "N/A";
      }
   }
}

var_dump($members);

Answer 2

You can use array_push function http://php.net/manual/en/function.array-push.php
foreach($members as $member)
  {
     foreach($member as $k => $v)
     {
       if($member[$k][$v] == null || trim($member[$k][$v]) == "")
       {
             array_push($member,'N/A');
        }
     }
  }

用文本替换多维数组中的空白空间

2 个答案: