我正在开发一个应该可以配置连接尝试超时的应用程序。
如果您查看下面的代码,您将意识到我正在尝试:等待20毫秒(此刻它是硬编码的),如果可以建立连接,则调用onConnected回调操作真正;否则为false(例如,如果发生超时)
internal void Connect(Action<bool> onConnected)
{
Func<AsyncCallback, object, IAsyncResult> beginConnect =
(callback, s) =>
{
var asyncResult = _socket.BeginConnect(Endpoint, callback, s);
var success = asyncResult.AsyncWaitHandle.WaitOne(20, true);
if(!success) throw new TimeoutException("Connection timeout");
return asyncResult;
};
var task = Task.Factory.FromAsync(beginConnect, _socket.EndConnect, this);
task.ContinueWith(t => onConnected(true), TaskContinuationOptions.NotOnFaulted)
.ContinueWith(t => onConnected(false), TaskContinuationOptions.OnlyOnFaulted);
task.ContinueWith(t => onConnected(false), TaskContinuationOptions.OnlyOnFaulted);
}
问题是由于beginConnect函数中的超时异常,从不调用回调。我想我可以在Connect方法调用者中用tyr-catch语句包装调用,但是它可以有几个调用者,并且在每个调用者看起来都是错误的。
我如何实现我想要的目标?
答案 0 :(得分:0)
我找到了实现我想要的方法:
internal void Connect(Action<bool> onConnected)
{
Func<AsyncCallback, object, IAsyncResult> beginConnect =
(callback, s) =>
{
var asyncResult = _socket.BeginConnect(Endpoint, callback, s);
var success = asyncResult.AsyncWaitHandle.WaitOne(20, true);
if(!success)
{
onConnected(false);
return default(IAsyncResult);
}
return asyncResult;
};
var task = Task.Factory.FromAsync(beginConnect, _socket.EndConnect, this);
task.ContinueWith(t => onConnected(true), TaskContinuationOptions.NotOnFaulted)
.ContinueWith(t => onConnected(false), TaskContinuationOptions.OnlyOnFaulted);
task.ContinueWith(t => onConnected(false), TaskContinuationOptions.OnlyOnFaulted);
}
重点是,在20ms之后,如果还没有连接,它会使用false调用回调并返回默认的IAsyncResult。