Question

我需要知道如何捕获以下xmlhttprequest

中的位置字段

Redirect
To:.....mp4
 with status: 302 Show explanation HTTP/1.1 302 Moved Temporarily
Redirection information has not been cached.
Server: Apache/2.2.14 (Ubuntu) 
Location:.....mp4
Content-Language: es-ES 
Content-Type: text/html; charset=ISO-8859-1 
Content-Length: 0 
Expires: Wed, 31 Jul 2013 10:04:15 GMT 
Date: Wed, 31 Jul 2013 10:02:13 GMT 
Connection: keep-alive
Vary: Accept-Encoding 
Status
200 OK Show explanation Loading time: 228
Request headers 
User-Agent: Mozilla/5.0 (Windows NT 6.2; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/28.0.1500.72 Safari/537.36
Content-Type: text/plain; charset=utf-8 
Accept: */*
Accept-Encoding: gzip,deflate,sdch
Accept-Language: es-ES,es;q=0.8
Cookie: odin=banebdyede; 
__utma=.....;
 __utmz=.....
Response headers 
Cache-Control: max-age=2592000 
Content-Length: 93692340 
Content-Type: video/mp4 
Expires: Fri, 30 Aug 2013 09:10:03 GMT 
Last-Modified: Tue, 25 Jun 2013 15:31:25 GMT 
Accept-Ranges: bytes 
Server: Apache/2.2.14 (Ubuntu) 
Date: Wed, 31 Jul 2013 10:02:13 GMT 
Connection: keep-alive

我使用该代码：

var req = new XMLHttpRequest();

    req.onreadystatechange = function (){
        try{
            if (req.status > 200){
                alert ("status mayor q 200!!!");
                }
        alert ('status: ' + req.status + ' ready: ' + req.readyState);
        if(req.readyState == 3 && req.status == 200){
            alert (req.getResponseHeader('Location'));
            alert (req.getAllResponseHeaders());
            req.abort();
            }
        if(req.readyState == 4 && req.status >= 300){
            alert ('entra!!');
            alert ('status: ' + req.status + ' ready: ' + req.readyState);
            alert (req.getResponseHeader('Location'));
            alert (req.getAllResponseHeaders());
            req.abort();
            }
        }catch (e){}
        }

    req.open('get', salida, true);
    req.send();

但状态永远不会超过200且状态为200，无法访问标题“位置”

任何解决方案？

感谢和抱歉我的英语

xmlhttprequest采用完整标头

0 个答案: