我必须使用两个按钮放置警报视图,但按钮不会打开网址。我不知道错误。请帮助。
以下是代码:
-(IBAction)showAlertView {
UIAlertView *alert = [[UIAlertView alloc]
initWithTitle:@"Obrir en..."
message:@"Es pot requirir la aplicació de Google Maps"
delegate:self
cancelButtonTitle:@"Millor no..."
otherButtonTitles:@"Mapes",@"Google Maps",nil];
[alert show];
}
- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{
NSString *title = [alertView buttonTitleAtIndex:buttonIndex];
if([title isEqualToString:@"Mapes"])
{
UIApplication *ourApplication = [UIApplication sharedApplication];
NSString *ourPath = @"http://maps.apple.com/?q=Plaça+del+Rei+43003+Tarragona";
NSURL *ourURL = [NSURL URLWithString:ourPath];
[ourApplication openURL:ourURL];
}
if([title isEqualToString:@"Google Maps"])
{
UIApplication *ourApplication = [UIApplication sharedApplication];
NSString *ourPath = @"comgooglemaps://?daddr=Plaça+del+Rei+43003+Tarragona&directionsmode=walking";
NSURL *ourURL = [NSURL URLWithString:ourPath];
[ourApplication openURL:ourURL];
}
}
答案 0 :(得分:1)
你必须对urlString进行url编码,因为它包含一些特殊字符。
NSString *ourPath = @"http://maps.apple.com/?q=Plaça+del+Rei+43003+Tarragona";
ourPath=[ourPath stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
答案 1 :(得分:0)
clickedButtonAtIndex...
是UIAlertView
的委托方法,此方法用于与UIAlertView
的选定按钮相关的点火操作
例如:
- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{
if(buttonIndex == 1)
{
/// write code for button 1 of UIAlertView; (here put 1 URL)
}
else if(buttonIndex == 2)
{
/// write code for button 2 of UIAlertView; (here put 2 URL)
}
}
那么,为什么你使用两个UIAlertView for TWO URL,将url放在UIAlertView
的委托方法中单击的单独按钮块中。
答案 2 :(得分:0)
我的发送网址错误
应该是
maps.google.com//?daddr=Plaça+del+Rei+43003+Tarragona&directionsmode=walking
代替
comgooglemaps://?daddr=Plaça+del+Rei+43003+Tarragona&directionsmode=walking
答案 3 :(得分:0)
NSString *enc = [match.location stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *location = [NSString stringWithFormat:@"%@%@", @"http://maps.google.com/maps?q=",enc];
NSLog(@"%@", location);
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:location]];