我正在尝试将WAVE文件加载到数据结构中,然后将其作为原始副本保存回磁盘。加载和保存似乎工作正常但复制的WAVE文件不会播放任何声音(尽管它确实打开没有错误)。我想知道这是否与endian-ness有关?
这是我保存WAVE文件的数据结构:
struct WaveFile
{
public:
static const uint16 NUM_CHARS = 4;
public:
WaveFile() : Data(nullptr) {}
~WaveFile() { delete[] Data; }
char ChunkID[NUM_CHARS];
uint32 ChunkSize;
char Format[NUM_CHARS];
char SubChunkID[NUM_CHARS];
uint32 SubChunkSize;
uint16 AudioFormat;
uint16 NumChannels;
uint32 SampleRate;
uint32 ByteRate;
uint16 BlockAlign;
uint16 BitsPerSample;
char SubChunk2ID[NUM_CHARS];
uint32 SubChunk2Size;
byte* Data;
};
这是我加载它的方式:
std::ifstream file(filename, std::ios::binary);
if (file.good())
{
file.read(waveFile.ChunkID, WaveFile::NUM_CHARS);
file.read(reinterpret_cast<char*>(&waveFile.ChunkSize), size_ui32);
file.read(waveFile.Format, WaveFile::NUM_CHARS);
file.read(waveFile.SubChunkID, WaveFile::NUM_CHARS);
file.read(reinterpret_cast<char*>(&waveFile.SubChunkSize), size_ui32);
file.read(reinterpret_cast<char*>(&waveFile.AudioFormat), size_ui16);
file.read(reinterpret_cast<char*>(&waveFile.NumChannels), size_ui16);
file.read(reinterpret_cast<char*>(&waveFile.SampleRate), size_ui32);
file.read(reinterpret_cast<char*>(&waveFile.ByteRate), size_ui32);
file.read(reinterpret_cast<char*>(&waveFile.BlockAlign), size_ui16);
file.read(reinterpret_cast<char*>(&waveFile.BitsPerSample), size_ui16);
file.read(waveFile.SubChunk2ID, WaveFile::NUM_CHARS);
file.read(reinterpret_cast<char*>(&waveFile.SubChunk2Size), size_ui32);
waveFile.Data = new byte[waveFile.SubChunk2Size];
file.read(reinterpret_cast<char*>(waveFile.Data), sizeof(waveFile.SubChunk2Size));
file.close();
}
这就是我将数据写回文件的方式:
std::ofstream file(outfile, std::ios::binary);
if (file.good())
{
file.flush();
file.write(waveFile.ChunkID, WaveFile::NUM_CHARS);
file.write(reinterpret_cast<const char*>(&waveFile.ChunkSize), size_ui32);
file.write(waveFile.Format, WaveFile::NUM_CHARS);
file.write(waveFile.SubChunkID, WaveFile::NUM_CHARS);
file.write(reinterpret_cast<const char*>(&waveFile.SubChunkSize), size_ui32);
file.write(reinterpret_cast<const char*>(&waveFile.AudioFormat), size_ui16);
file.write(reinterpret_cast<const char*>(&waveFile.NumChannels), size_ui16);
file.write(reinterpret_cast<const char*>(&waveFile.SampleRate), size_ui32);
file.write(reinterpret_cast<const char*>(&waveFile.ByteRate), size_ui32);
file.write(reinterpret_cast<const char*>(&waveFile.BlockAlign), size_ui16);
file.write(reinterpret_cast<const char*>(&waveFile.BitsPerSample), size_ui16);
file.write(waveFile.SubChunk2ID, WaveFile::NUM_CHARS);
file.write(reinterpret_cast<const char*>(&waveFile.SubChunk2Size), size_ui32);
file.write(reinterpret_cast<const char*>(waveFile.Data), waveFile.SubChunk2Size);
file.close();
}
副本的大小也与原始大小相同。如果有人想知道,uint16,uint32和byte只是unsigned short,unsigned int和unsigned char的typedef。 size_ui32变量就是这样的:
static const uint32 size_ui32 = sizeof(uint32);
static const uint32 size_ui16 = sizeof(uint16);
不管怎样,似乎无法找出我出错的地方。
欢呼任何帮助。
答案 0 :(得分:1)
这适用于大多数wavefiles,但某些标头可能包含特定的用户数据。你可以使用struct WAVEHEADER的sigle写:
struct WAVEFILEHEADER
{
// don't change the order of attributes
char m_lpcChunkId[4];
int m_iChunkSize;
char m_lpcFormat[4];
char m_lpcSubChunkFmt[4];
int m_iSubChunkFmtSize;
short int m_siAudioFormat;
short int m_siNumChannels;
int m_iSampleRate;
int m_iByteRate;
short int m_siBlockAlign;
short int m_siBitsPerSample;
char m_lpcChunkData[4];
int m_iSubChunkDataSize;
// unsigned char * m_data;
};
WAVEFILEHEADER whdr;
FILE* fid = fopen("newaudio.wav","wb"); // important to use binary file
// some inicialization for whdr - RIFF etc.
// You can use only 1 write to save whole header:
fwrite(&whdr, 1, sizeof(WAVEFILEHEADER), fid);
// or you can read wav header
fread(&whdr, 1, sizeof(WAVEFILEHEADER), fid);
// check chunk size, few headers have aditional 2 bytes (by definition user data, but they was always 0x0000)
答案 1 :(得分:0)
发布此问题后,我刚刚发现了问题。
在阅读数据时,我已经完成了这个:
file.read(reinterpret_cast<char*>(waveFile.Data), sizeof(waveFile.SubChunk2Size));
应该是:
file.read(reinterpret_cast<char*>(waveFile.Data), waveFile.SubChunk2Size);
删除sizeof()后工作。傻我。