Question

好的，今天我编辑了这段代码，以便用户可以更改自己的电子邮件地址。他们更改了电子邮件地址后，会向用户发送确认电子邮件。但是，我被重定向到内部错误500页。：\任何帮助？我没有看到代码有什么问题..

<?php

include("session.php");
//Create game account
$mysqli = new mysqli("localhost", "root", "password", "data");

if(mysqli_connect_errno()){
    echo("Sorry, the server is 'Under Maintainance'");
    exit();
}

$newemail = $mysqli->real_escape_string($_POST['email']);
$newemail = strtolower($newemail);
$password = $mysqli->real_escape_string($_POST['password']);
$hash     = sha1(strtolower($name) . $password);

if(!isset($name)){
    header("Location:index");
}else if($password == null || $password == "" || (strlen($password)) < 4 || strpos($password, '<') !== false || strpos($password, '>') !== false){
    header("Location:cemail?error=6");//Invalid password
}else if($newemail == null || $newemail == "" || (strlen($newemail) <= 6 || strpos($newemail, '<') !== false || strpos($newemail, '>') !== false) || strpos($newemail, '@') == false || strpos($newemail, ".com") == false){
    header("Location:cemail?error=7");//Invalid Email address
}else if($email == $newemail){
    header("Location:cemail?error=7");//Invalid Email address
}else{
    $result  = $mysqli->query("SELECT * FROM characters WHERE email='$newemail' && name!='$name");
    $row_cnt = $result->num_rows;
    $result->free();

    if($row_cnt != 0){
        header("Location:cemail?error=3");//Email already taken
    }else{

        $result  = $mysqli->query("SELECT * FROM characters WHERE originemail='$newemail' && name!='$name'");
        $row_cnt = $result->num_rows;
        $result->free();

        if($row_cnt != 0){
            header("Location:cemail?error=3");//Email already taken
        }else{

            $result = $mysqli->query("SELECT * FROM characters WHERE name='$name'");

            /* fetch associative array */
            while($row = $result->fetch_assoc()){
                $pass        = $row['pass'];
                $originemail = $row['originemail'];
            }

            /* free result set */
            $result->free();

            if($hash != $pass){
                header("Location:cemail?error=6");//Invalid Password Match
            }else{
                $mysqli->query("UPDATE characters SET email='$newemail' WHERE name='$name'");

//Send Email to confirm 
                $to      = $newemail . ", " . $originemail;
                $subject = "Your email address has now been successfully changed!";
                $body    = "This is a notification regarding the recent change(s) made to your Legion Online account: " . $username . "
\n\n
Your email address has recently been modified through the Legion Online website. If you made this email address change, please disregard this notification. If you did not change your email address, please visit the account recovery page to ensure your account is secure.\n\nEmail addresses connected to this account: \n" . $originemail . "(primary)\n" . $newemail;
                $headers = "From: AccountSupport@ArchStudios.net" . "\r\n";
                if(mail($to, $subject, $body, $headers)){
                    header("Location:accountsettings");
                }else{
                    echo "Email request failed.";
                }
            }
        }
    }
}
$mysqli->close();
?>

Answer 1

你只有一个变量$ name的引用：

$result=$mysqli->query("SELECT * FROM characters WHERE email='$newemail' && name!='$name");

复制此：

$result=$mysqli->query("SELECT * FROM characters WHERE email='$newemail' && name!='$name'");

Answer 2

不要忘记关闭单/双引号。

替换

$mysqli = new mysqli("localhost", "root", "password", "data);
$result  = $mysqli->query("SELECT * FROM characters WHERE email='$newemail' && name!='$name");

通过

$mysqli = new mysqli("localhost", "root", "password", "data");
$result  = $mysqli->query("SELECT * FROM characters WHERE email='$newemail' && name!='$name'");

我的电子邮件验证码有什么问题？

2 个答案: