Question

我正在尝试从另一个类调用一个方法。当我选择此菜单选项时，p.players()应该会打开：

 static void Main(string[] args)
    {

        Enumfactory.Position choice;
        Enumfactory.Location location;
        Player p = new Player();


        Console.WriteLine("Please choose from one of the following:");
        Console.WriteLine("1. GoalKeeper");
        Console.WriteLine("2. Defender");
        Console.WriteLine("3. Midfielder");
        Console.WriteLine("4. Striker");
        choice = ((Enumfactory.Position)(int.Parse(Console.ReadLine())));

        string exit = "";

        while (exit != "Y")
        {

            switch (choice)
            {
                case Enumfactory.Position.GoalKeeper:
                    //assigning the actual position
                    p.Position = Enumfactory.Position.GoalKeeper;
                    p.players();
                    break;

以下是来自Player类的方法：

public string[] players()
    {
        List<string> PlayerList = new List<string>();
        Player player = new Player();
        string enterplayer = "";
        while (enterplayer == "Y")
        {
            Console.WriteLine("Please enter the teamnumber of your player");
            player.teamNumber = int.Parse(Console.ReadLine());
            Console.WriteLine("Please enter the name of your player");
            player.name = Console.ReadLine();
            Console.WriteLine("Please enter the surname of your player");
            player.surname = Console.ReadLine();
            Console.WriteLine("Enter the age of your player");
            player.age = int.Parse(Console.ReadLine());
            Console.WriteLine("Please enter the goals the player scored");
            player.goalsScored = int.Parse(Console.ReadLine());

            PlayerList.Add(player.teamNumber.ToString());
            PlayerList.Add(player.name);
            PlayerList.Add(player.surname);
            PlayerList.Add(player.age.ToString());
            PlayerList.Add(player.goalsScored.ToString());

            Console.WriteLine("Do you wish to enter another player? Y/N");
            enterplayer = Console.ReadLine();
        }
        foreach (var item in PlayerList)
        {
            Console.WriteLine("to view your player");
            Console.Write("{0}", item);
        }
        Console.ReadKey();
        return player.players();
    }

Answer 1

该方法可能正在被调用，它只是你的while循环永远不会运行。这是因为enterplayer永远不会等于＆＃34; Y＆＃34;因此，你的while循环中的代码将永远不会运行（这使得它看起来像你的方法没有被调用）。

您的意思是以下吗？

string enterplayer = "";
while (enterplayer != "Y")
{
    ...
}

Answer 2

您编写它的方式中的while循环将在第一次进入循环之前评估条件。您将enterplayer初始化为""，因此第一次测试while条件时它会返回false并且永远不会进入循环。您可以通过两种方式解决此问题，方法是初始化enterplayer，以便第一次满足条件：

string enterplayer = "Y";
while (enterplayer == "Y") // We set enterplayer to "Y" so this is true first time through
{
    // Your code to add a player goes here
}

...或者，您可以使用稍微不同的while循环形式，最后评估条件。这意味着循环中的代码总是至少执行一次，然后只要满足最后while条件就重复：

string enterplayer = "";
do // This always enters the loop code first time
{
    // Your code to add a player goes here
}
while (enterplayer == "Y")

由于您的代码使用enterplayer变量决定是否添加更多玩家，我更喜欢第二种形式，即使作为while构造的变体，它可能不如前者。

来自另一个类的方法不会调用

2 个答案: