Question

我的选择看起来像这样，它返回最大id ...

中的字段

SELECT * FROM Pontos WHERE IdPonto = (SELECT MAX(IdPonto) FROM Pontos)

但现在我想只选择第二大的字段。

Answer 1

SELECT * FROM Pontos WHERE IdPonto = (SELECT IdPonto FROM Pontos ORDER BY IdPonto DESC LIMIT 1,1)应该有用。

Answer 2

这是一种方法：

SELECT * FROM Pontos ORDER BY Id DESC LIMIT 1 OFFSET 1

（不太确定sqlite语法，但请阅读此SO线程以获取更多信息：Sqlite LIMIT / OFFSET query）

编辑：我不认为在这种情况下运行嵌套查询是必要的。

Answer 3

这是用标准SQL编写的（它不使用LIMIT和OFFSET），应该可以工作：

SELECT * FROM Pontos WHERE IdPontos = (
    SELECT MAX(t1.IdPontos) FROM Pontos t1
    WHERE t1.IdPontos not in (SELECT MAX(IdPontos) FROM Pontos)
)

Answer 4

我似乎在标准SQL和SQLite中完成了这项工作。

select * from Pontos where IdPonto < (select max(IdPonto) from Pontos) and IdPonto = (select max(IdPonto) from Pontos where IdPonto < (select max(IdPonto) from Pontos));

希望它有所帮助。

Answer 5

SELECT * FROM Pontos ORDER BY IdPonto DESC LIMIT 1,1

SQL：SELECT SECOND BIGGEST ID中的所有字段

5 个答案: