我一直在关注CS193P Stanford iOS开发讲座,在第二项任务“Set”中,我无法弄清楚我的程序在按钮上显示属性字符串有什么问题。出于某种原因,当我的字符串试图显示3个字符时,它最终显示为1个大字符和3个随机的其他字符。当我只想要红色,绿色和蓝色字符时,许多字符显示为黑色。如果有人能够建立这个项目并帮助我弄清楚发生了什么,我将不胜感激。我花了大约4个小时试图调试这个。来源是 https://github.com/zhumatthew/MatchSet
问题出在标签栏中第二个标签的设置视图控制器下。
感谢。
http://postimg.org/image/gs7qley3r/
#import "SetViewController.h"
#import "SetCardDeck.h"
#import "SetCard.h"
@interface SetViewController ()
@property (strong, nonatomic) IBOutletCollection(UIButton) NSArray *cardButtons;
@end
@implementation SetViewController
@synthesize deck = _deck;
- (Deck *)deck {
if (!_deck) _deck = [[SetCardDeck alloc] init];
return _deck;
}
- (void)updateUI {
[super updateUI];
for (UIButton *cardButton in self.cardButtons) {
UIColor *foregroundColor;
UIColor *strokeColor;
SetCard *card = (SetCard *)[self.game cardAtIndex:[self.cardButtons indexOfObject:cardButton]];
NSString *string = [[NSString alloc] init];
for (int i = 0; i < card.number; i++) {
string = [NSString stringWithFormat:@"%@%@", string, card.symbol];
}
if ([card.color isEqualToString:@"R"]) {
foregroundColor = [UIColor redColor];
} else if ([card.color isEqualToString:@"G"]) {
foregroundColor = [UIColor greenColor];
} else if ([card.color isEqualToString:@"B"]) {
foregroundColor = [UIColor blueColor];
}
strokeColor = [foregroundColor copy];
if ([card.shading isEqualToString:@"S"]) {
foregroundColor = [foregroundColor colorWithAlphaComponent:1];
} else if ([card.shading isEqualToString:@"H"]) {
foregroundColor = [foregroundColor colorWithAlphaComponent:0.3];
} else if ([card.shading isEqualToString:@"O"]) {
foregroundColor = [foregroundColor colorWithAlphaComponent:0];
}
NSAttributedString *mat = [[NSAttributedString alloc] initWithString:string attributes:@{NSForegroundColorAttributeName:foregroundColor,NSStrokeWidthAttributeName:@-5,NSStrokeColorAttributeName:strokeColor}];
[cardButton setAttributedTitle:mat forState:UIControlStateNormal];
CGFloat red;
CGFloat green;
CGFloat blue;
CGFloat alpha;
[foregroundColor getRed:&red green:&green blue:&blue alpha:&alpha];
NSLog(@"red:%f green:%f blue:%f alpha:%f index:%d",red,green,blue,alpha,[self.cardButtons indexOfObject:cardButton]);
[strokeColor getRed:&red green:&green blue:&blue alpha:&alpha];
NSLog(@"red:%f green:%f blue:%f alpha:%f ",red,green,blue,alpha);
NSLog(@"%@",[mat string]);
cardButton.selected = card.isFaceUp;
cardButton.enabled = !card.isUnplayable;
if (card.isFaceUp) {
[cardButton setBackgroundColor:[UIColor lightGrayColor]];
} else {
[cardButton setBackgroundColor:[UIColor whiteColor]];
}
}
}
@end
答案 0 :(得分:1)
据我所见,有两个不同的问题:
在iOS 6上,某些字符(例如“◼”符号)显示为“Apple Color Emoji”。 这是一个(有争议的讨论)“特征”,参见例如https://devforums.apple.com/message/487463#487463(需要Apple Developer登录)。 因此,颜色等属性将被忽略。
可以通过附加来抑制表情符号替换(来自UILabel, UIFont and UTF-8 Triangle) Unicode“变体选择器”U + FE0E:
+ (NSArray *)validSymbols {
return @[@"◼\uFE0E",@"●",@"▲"];
}
通过此更改,您的所有符号都会按预期正确显示。